2(8), 2(8) N,O;(g) → 2 NO,(g) + ¿ O2(g) ¿0g]/10-² M [NO,]/10-2 M [0,]/10-² M 1.24 0.92 0.64 0.16 0.68 1.12 0.28 0.50 1.48 0.37 0.37 1.74 0.44 0.28 1.92 0.48 0.21 2.06 0.52 0.14 2.18 0.55 0.11 2.26 0.57 0.08 2.32 0.58 0.06 2.36 0.59
2(8), 2(8) N,O;(g) → 2 NO,(g) + ¿ O2(g) ¿0g]/10-² M [NO,]/10-2 M [0,]/10-² M 1.24 0.92 0.64 0.16 0.68 1.12 0.28 0.50 1.48 0.37 0.37 1.74 0.44 0.28 1.92 0.48 0.21 2.06 0.52 0.14 2.18 0.55 0.11 2.26 0.57 0.08 2.32 0.58 0.06 2.36 0.59
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Using the initial concentrations and the fact that [O2] = 0.55 × 10–2 M at t = 70.0 minutes in Table 17.2, calculate [N2O5] and [NO2] at t = 70.0 minutes.
![TABLE 17.2 Concentrations of N,0s(g), NO,(g), and O2(g) as a function of time at
45°C for the reaction
N,O5(g) → 2 NO,(g) +;O2(g)
t/min
[N,O;]/10-2 M
[NO,]/10-2 M
[02]/10-2 M
1.24
10.0
0.92
0.64
0.16
20.0
0.68
1.12
0.28
30.0
0.50
1.48
0.37
40.0
0.37
1.74
0.44
50.0
0.28
1.92
0.48
60.0
0.21
2.06
0.52
70.0
0.14
2.18
0.55
80.0
0.11
2.26
0.57
90.0
0.08
2.32
0.58
100.0
0.06
2.36
0.59](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc61ac136-beb0-491a-99b0-c53254daee6a%2F0ad14bfe-2c4c-4af0-b550-0fb8d929a16d%2F6gnhkoh_processed.png&w=3840&q=75)
Transcribed Image Text:TABLE 17.2 Concentrations of N,0s(g), NO,(g), and O2(g) as a function of time at
45°C for the reaction
N,O5(g) → 2 NO,(g) +;O2(g)
t/min
[N,O;]/10-2 M
[NO,]/10-2 M
[02]/10-2 M
1.24
10.0
0.92
0.64
0.16
20.0
0.68
1.12
0.28
30.0
0.50
1.48
0.37
40.0
0.37
1.74
0.44
50.0
0.28
1.92
0.48
60.0
0.21
2.06
0.52
70.0
0.14
2.18
0.55
80.0
0.11
2.26
0.57
90.0
0.08
2.32
0.58
100.0
0.06
2.36
0.59
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