In a location in outer space far from all other objects, a nucleus whose mass is 3.835264e-25 kg and which is initially at rest undergoes spontaneous "alpha" decay. The original nucleus disappears, and two new particles appear: a He-4 nucleus of mass 6.640678e-27 kg (an "alpha particle" consisting of two protons and two neutrons) and a new nucleus of mass 3.768771e-25 kg. These new particles move far away from each other, because they repel each other electrically (both are positively charged). Because the calculations involve the small difference of (comparatively) large numbers, you need to keep 7 significant figures in your calculations, and you need to use the more accurate value for the speed of light, 2.99792e8 m/s. Choose all particles as the system. Initial state: Original nucleus, at rest. Final state: Alpha particle + new nucleus, far from each other. What is the rest energy of the original nucleus? Give 7 significant figures. rest energy = 49 What is the sum of the rest energies of the alpha particle and the new nucleus? Give 7 significant figures. sum of rest energies = The portion of the total energy of the system contributed by rest energy: -Select---

icon
Related questions
Question
In a location in outer space far from all other objects, a nucleus whose mass is \(3.835264 \times 10^{-25}\) kg and which is initially at rest undergoes spontaneous "alpha" decay. The original nucleus disappears, and two new particles appear: a He-4 nucleus of mass \(6.640678 \times 10^{-27}\) kg (an "alpha particle" consisting of two protons and two neutrons) and a new nucleus of mass \(3.768771 \times 10^{-25}\) kg. These new particles move far away from each other because they repel each other electrically (both are positively charged).

Because the calculations involve the small difference of (comparatively) large numbers, you need to keep 7 significant figures in your calculations, and you need to use the more accurate value for the speed of light, \(2.99792 \times 10^8\) m/s.

**Choose all particles as the system:**
- Initial state: Original nucleus, at rest.
- Final state: Alpha particle + new nucleus, far from each other.

**Questions:**

1. What is the rest energy of the original nucleus? *Give 7 significant figures.*
   - Rest energy = \([ \text{Your Answer} ]\) J

2. What is the sum of the rest energies of the alpha particle and the new nucleus? *Give 7 significant figures.*
   - Sum of rest energies = \([ \text{Your Answer} ]\) J

3. The portion of the total energy of the system contributed by rest energy: \([ \text{Select} \])
   - Therefore, the portion of the total energy of the system contributed by kinetic energy: \([ \text{Select} \])

4. What is the sum of the kinetic energies of the alpha particle and the new nucleus?
   - \( K_{\text{alpha}} + K_{\text{new nucleus}} = [ \text{Your Answer} ] \)
Transcribed Image Text:In a location in outer space far from all other objects, a nucleus whose mass is \(3.835264 \times 10^{-25}\) kg and which is initially at rest undergoes spontaneous "alpha" decay. The original nucleus disappears, and two new particles appear: a He-4 nucleus of mass \(6.640678 \times 10^{-27}\) kg (an "alpha particle" consisting of two protons and two neutrons) and a new nucleus of mass \(3.768771 \times 10^{-25}\) kg. These new particles move far away from each other because they repel each other electrically (both are positively charged). Because the calculations involve the small difference of (comparatively) large numbers, you need to keep 7 significant figures in your calculations, and you need to use the more accurate value for the speed of light, \(2.99792 \times 10^8\) m/s. **Choose all particles as the system:** - Initial state: Original nucleus, at rest. - Final state: Alpha particle + new nucleus, far from each other. **Questions:** 1. What is the rest energy of the original nucleus? *Give 7 significant figures.* - Rest energy = \([ \text{Your Answer} ]\) J 2. What is the sum of the rest energies of the alpha particle and the new nucleus? *Give 7 significant figures.* - Sum of rest energies = \([ \text{Your Answer} ]\) J 3. The portion of the total energy of the system contributed by rest energy: \([ \text{Select} \]) - Therefore, the portion of the total energy of the system contributed by kinetic energy: \([ \text{Select} \]) 4. What is the sum of the kinetic energies of the alpha particle and the new nucleus? - \( K_{\text{alpha}} + K_{\text{new nucleus}} = [ \text{Your Answer} ] \)
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps

Blurred answer
Similar questions
  • SEE MORE QUESTIONS