In a cohesionless soil deposit with a unit weight of 15kN /(m ^2) and an angle of internal friction of 30°, the active and passive earth pressures (in kN /(m ^2)) at a depth of 10 m will be?

The water table in a deposit of uniform sand is located at 2 m below the ground level. Assuming the soil above the water table be dry and the void ratio is 0.75. The effective stress (in kN/m2, rounded off to nearest integer) at a depth of 5 m below the ground level is (upto 2 decimal places), Take G = 2.65 and Y₁ =9.81 kN/m².

EFFECTIVE STRESS CONCEPT SITUATION 1: A saturated clay 15 m thick has a void ratio of 0.6 anda specific gravity of 2.7. 5. Which of the following gives the saturated unit weight of clay? a. 18.95 kN/m? C. 20.23 kN/m? b. 19.18 kN/m? d. 24.22 kN/m? 6. Which of the following gives the total vertical stress at the bottom? a. 303.45 kPa C. 355.66 kPa b. 295.66 kPa d. 145.67 kPa 7. Which of the following gives the effective vertical stress at the bottom? a. 197.33 kPa c. 177.21 kPa b. 187.95 kPa d. 156.34 kPa

A)Plot graphically all the vertical stresses, pore water and effective vertical stresses throughout the depth. B)How would the effective vertical stress value at the midpoint of the clay layer change if the groundwater level increased 2 m? (g = 10 m / s2)

c) For the soil deposit shown below, determine the magnitude of the following total stress pore water pressure and effective stress. The water table is at ground level 0 m Layer 1 Ysat = 1.92 T/m? %3D .4 m Layer 2 Ysat = 2.1 T/ m? -11m.

Solve this soil problem

How should the groundwater table move to have an effective stress of 95kPA, 2m from the bottom of the profile? For specific gravity, Gs = 2.68.

Solve fast

Q1 (a)

I need the answer as soon as possible