Homework Help is Here – Start Your Trial Now!
Engineering
Data Structures and Algorithms
Implement in C Programming 8.2.2: Printing with pointers. If the input is negative, make numItemsPointer be null. Otherwise, make numItemsPointer point to numItems and multiply the value to which numItemsPointer points by 10. Ex: If the user enters 99, the output should be:Items: 990 #include int main(void) {    int* numItemsPointer;    int numItems;    scanf("%d", &numItems);    /* Your solution goes here  */    if (numItemsPointer == NULL) {       printf("Items is negative\n");    }    else {       printf("Items: %d\n", *numItemsPointer);    }    return 0;

Implement in C Programming 8.2.2: Printing with pointers. If the input is negative, make numItemsPointer be null. Otherwise, make numItemsPointer point to numItems and multiply the value to which numItemsPointer points by 10. Ex: If the user enters 99, the output should be:Items: 990 #include int main(void) {    int* numItemsPointer;    int numItems;    scanf("%d", &numItems);    /* Your solution goes here  */    if (numItemsPointer == NULL) {       printf("Items is negative\n");    }    else {       printf("Items: %d\n", *numItemsPointer);    }    return 0;

icon
Related questions
Question
100%

Implement in C Programming

8.2.2: Printing with pointers.

If the input is negative, make numItemsPointer be null. Otherwise, make numItemsPointer point to numItems and multiply the value to which numItemsPointer points by 10. Ex: If the user enters 99, the output should be:Items: 990

#include <stdio.h>

int main(void) {
   int* numItemsPointer;
   int numItems;

   scanf("%d", &numItems);

   /* Your solution goes here  */

   if (numItemsPointer == NULL) {
      printf("Items is negative\n");
   }
   else {
      printf("Items: %d\n", *numItemsPointer);
   }

   return 0;
}

Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer