Pointers There follows a program with headers omitted. However, a question mark needs to be replaced with a number in order for the program to compile and run. int nain(void){ int a= 1; int b = 2; C = 3; *d- &c; int int int *e = &b; int *+ &e; *f= ?; int **g = &d; d= &a; **g - c; e = &c; 4= a + b; printf("a = Xdb = Xd c = Xd", a, b, c); If the value for printed for c is 9 Then the value chosen for the ? was the value printed for a is and the value printed for b is
Pointers There follows a program with headers omitted. However, a question mark needs to be replaced with a number in order for the program to compile and run. int nain(void){ int a= 1; int b = 2; C = 3; *d- &c; int int int *e = &b; int *+ &e; *f= ?; int **g = &d; d= &a; **g - c; e = &c; 4= a + b; printf("a = Xdb = Xd c = Xd", a, b, c); If the value for printed for c is 9 Then the value chosen for the ? was the value printed for a is and the value printed for b is
C++ for Engineers and Scientists
4th Edition
ISBN:9781133187844
Author:Bronson, Gary J.
Publisher:Bronson, Gary J.
Chapter8: I/o Streams And Data Files
Section: Chapter Questions
Problem 8PP: (Data processing) A bank’s customer records are to be stored in a file and read into a set of arrays...
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Question
![Pointers
There follows a program with headers omitted.
However, a question mark needs to be replaced with a number in order for the program to compile and run.
int main(void){
int
a 1;
int
b = 2;
int
C = 3;
int d &c;
int
*e = &b;
int *+ &e;
***= ?;
int **g = &d;
d = &a;
**g- c;
e = &c:
4= a + b;
printf("a = Xdb = Xd c = Xd", a, b, c);
If the value for printed for c is 9
Then the value chosen for the ? was
the value printed for a is
and the value printed for b is](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd6465a54-1657-4d08-a17a-1464572577f0%2F68c005ea-2ff8-427c-917e-7b65b208d00b%2Fdbaupys_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Pointers
There follows a program with headers omitted.
However, a question mark needs to be replaced with a number in order for the program to compile and run.
int main(void){
int
a 1;
int
b = 2;
int
C = 3;
int d &c;
int
*e = &b;
int *+ &e;
***= ?;
int **g = &d;
d = &a;
**g- c;
e = &c:
4= a + b;
printf("a = Xdb = Xd c = Xd", a, b, c);
If the value for printed for c is 9
Then the value chosen for the ? was
the value printed for a is
and the value printed for b is
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