If you use a 0.05 level of significance in a two-tail hypothesis test, what decision will you make if ZSTAT=−1.52? Determine the decision rule.
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If you use a 0.05 level of significance in a two-tail hypothesis test, what decision will you make if ZSTAT=−1.52?
Determine the decision rule.
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- The proportion of commuters on is purported to be 65%. A professor believes this to be inaccurate. He randomly selects 300 students on campus and determines 200 of them to be commuters. Can the professor reject the campus claim of 65%? Write the hypotheses for this scenario. Is this one tailed or two tailed? Why? What statistical test would be used for this scenario? Explain why.A nutrition expert claims that the average American is overweight: To test his claim, a random sample of 25 Americans was selected, and the difference between each person's actual weight and idea weight was calculated. For this data, we have = 16 and 8 = 28.4. Is there sufficient evidence to conclude that the expert's claim is true? Carry out a hypothesis test at a 8% significance level. Hint: Pay attention to the variable being measured: the difference between actual weight and ideal. A positive value indicates that the person is overweight. A. The value of the standardized test statistic (give to 3 decimal places): B. The p-value is (give to 4 decimal places): C. Your decision for the hypothesis test: O A. Reject Ho- OB. Reject Ha C. Do Not Reject Ha- O D. Do Not Reject Ho- EOne study claimed that 88 % of college students identify themselves as procrastinators. A professor believes that the claim regarding college students is too high. The professor conducts a simple random sample of 272 college students and finds that 231 of them identify themselves as procrastinators. Does this evidence support the professor's claim that fewer than 88 % of college students are procrastinators? Use a 0.02 level of significance. Step 2 of 3: Compute the value of the test statistic. Round your answer to two decimal places.
- One study claimed that 86% of college students identify themselves as procrastinators. A professor believes that the claim regarding college students is too high. The professor conducts a simple random sample of 238 college students and finds that 193 of them identify themselves as procrastinators. Does this evidence support the professor’s claim that fewer than 86% of college students are procrastinators? Use a 0.05 level of significance. Step 2 of 3 : Compute the value of the test statistic. Round your answer to two decimal places.A simple random sample of 300 men included 71 who smoke, and a simple random sample of 310 women included 68 who smoke. Use a .05 level of significance to test the claim that the proportion of men who smoke is greater than the proportion of women who smoke.With the null hypothesis that a suspect is innocent, an investigation concluded that the suspect should not be convicted at 5% level of significance. The conclusion would be the same if tested at 1% level of significance. Select one: True False
- A sociologist claims that the students’ college GPA’s in unrelated to their families’ incomes. For a random sample of 20 students the coefficient of correlation was computed as 0.40. Using the 0.01 significance level, do the formal hypothesis test.Remember to show your steps (including all relevant information) show the steps on how to solve itAccording to the most recent General Social Survey, 70% of adults watch TV nightly. A researcher believes that the proportion of college students who watch TV nightly is less than this. To test this claim the research samples 400 college students and finds that 276 watch TV nightly. At the 0.05 level of significance does this data provide evidence to suggest that the proportion of college students who watch TV nightly is less than 70%? Select the correct hypothesis test for this problem:Suppose a study reported that the average persin watched 3.37 hours of television per day. a random sample of 15 people gave the number of hours of television watched per day shown below. at the 1% significance level, do the data provide sufficent evidence to conclude that the amount of television watched per day last year by the average person is greater than the value reported in the study? what is the test statistic value for this problem? a.0.28 b.-38 c.none of the above d. 0.58 e.-4.295 f..04 g. 1.94 . the proper conclusion for this problem is? a. reject the null hypothesis we have sufficent evidence to prove the average number of hours people watch tv is more than 3.37 hours. b. Do not reject the null hypothesis we have sufficient evidence to prove the average number of hours of TV watched is greater than 3.37 hours c. Reject the null hypothesis and claim the average number of hours people watch TV is less than 3.37 because the P value is near zero d. Do not reject the null…
- Z?Suppose a study reported that the average person watched 3.34 hours of television per day. A random sample of 15 people gave the number of hours of television watched per day shown. At the 10% significance level, do the data provide sufficient evidence to conclude that the amount of television watched per day last year by the average person differed from the value reported in the study? (Note: x = 4.400 hours and s= 1.262 hours.) Set up the hypotheses for the one-mean t-test. HoiH Ha: H 2.3 4.0 4.5 4.9 5.0 4.5 3.3 2.0 5.7 5.9 6.2 3.8 5.9 3.9 4.1The coach of a very popular men’s basketball team claims that the average distance the fans travel to the campus to watch a game is 35 miles. The team members feel otherwise. A sample of 16 fans who travel to games was randomly selected and yielded a mean of M= 36 miles and s= 5 miles. Test the coach’s claim at the 5% (.05) level of significance. one-tailed or two-tailed test: State the hypotheses: df= tα or t value for the critical region = sM = t (test statistic)= Decision: