In a clinical trial of a drug intended to help people stop​ smoking, 131 subjects were treated with the drug for 13 weeks, and 13 subjects experienced abdominal pain. If someone claims that more than 8​% of the drug's users experience abdominal​ pain, that claim is supported with a hypothesis test conducted with a 0.05 significance level. Using 0.18 as an alternative value of​ p, the power of the test is 0.96. Interpret this value of the power of the test.

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In a clinical trial of a drug intended to help people stop​ smoking, 131 subjects were treated with the drug for 13 weeks, and 13 subjects experienced abdominal pain. If someone claims that more than 8​% of the drug's users experience abdominal​ pain, that claim is supported with a hypothesis test conducted with a 0.05 significance level. Using 0.18 as an alternative value of​ p, the power of the test is 0.96.

Interpret this value of the power of the test.

15. In a clinical trial of a drug intended to help people stop smoking, 131 subjects were treated with the drug for 13 weeks, and 13 subjects experienced abdominal pain. If someone claims that
more than 8% of the drug's users experience abdominal pain, that claim is supported with a hypothesis test conducted with a 0.05 significance level. Using 0.18 as an alternative value of p.
the power of the test is 0.96. Interpret this value of the power of the test.
% chance of rejecting the (1)
That is, if the proportion of users who experience abdominal pain is actually
than 0.08.
The power of 0.96 shows that there is a
proportion of users who experience abdominal pain is (2)
(Type integers or decimals. Do not round.)
(1) O alternative (2) O less
O null
O greater
hypothesis of p =
then there is a
when the true proportion is actually
% chance of supporting the claim that the
Transcribed Image Text:15. In a clinical trial of a drug intended to help people stop smoking, 131 subjects were treated with the drug for 13 weeks, and 13 subjects experienced abdominal pain. If someone claims that more than 8% of the drug's users experience abdominal pain, that claim is supported with a hypothesis test conducted with a 0.05 significance level. Using 0.18 as an alternative value of p. the power of the test is 0.96. Interpret this value of the power of the test. % chance of rejecting the (1) That is, if the proportion of users who experience abdominal pain is actually than 0.08. The power of 0.96 shows that there is a proportion of users who experience abdominal pain is (2) (Type integers or decimals. Do not round.) (1) O alternative (2) O less O null O greater hypothesis of p = then there is a when the true proportion is actually % chance of supporting the claim that the
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