In a clinical trial of a drug intended to help people stop smoking, 127 subjects were treated with the drug for 11 weeks, and 11 subjects experienced abdominal pain. If someone claims that more than 8% of the drug's users experience abdominal pain, that claim is supported with a hypothesis test conducted with a 0.05 significance level. Using 0.17 as an alternative value of p, the power of the test is 0.95. Interpret this value of the power of the test. chance of rejecting the hypothesis of p = when the The power of 0.95 shows that there is a true proportion is actually. That is, if the proportion of users who experience abdominal pain is actually then there is a % chance of supporting the claim that the proportion of users who experience abdominal pain is than 0.08. (Type integers or decimals. Do not round.)

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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Chapter1: Starting With Matlab
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In a clinical trial of a drug intended to help people stop smoking, 127 subjects were treated with the drug for 11
weeks, and 11 subjects experienced abdominal pain. If someone claims that more than 8% of the drug's users
experience abdominal pain, that claim is supported with a hypothesis test conducted with a 0.05 significance level.
Using 0.17 as an alternative value of p, the power of the test is 0.95. Interpret this value of the power of the test.
chance of rejecting the
hypothesis of p = when the
The power of 0.95 shows that there is a
true proportion is actually. That is, if the proportion of users who experience abdominal pain is actually then
there is a % chance of supporting the claim that the proportion of users who experience abdominal pain is
than 0.08.
(Type integers or decimals. Do not round.)
Transcribed Image Text:In a clinical trial of a drug intended to help people stop smoking, 127 subjects were treated with the drug for 11 weeks, and 11 subjects experienced abdominal pain. If someone claims that more than 8% of the drug's users experience abdominal pain, that claim is supported with a hypothesis test conducted with a 0.05 significance level. Using 0.17 as an alternative value of p, the power of the test is 0.95. Interpret this value of the power of the test. chance of rejecting the hypothesis of p = when the The power of 0.95 shows that there is a true proportion is actually. That is, if the proportion of users who experience abdominal pain is actually then there is a % chance of supporting the claim that the proportion of users who experience abdominal pain is than 0.08. (Type integers or decimals. Do not round.)
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