One study claimed that 88 % of college students identify themselves as procrastinators. A professor believes that theclaim regarding college students is too high. The professor conducts a simple random sample of 272 college studentsand finds that 231 of them identify themselves as procrastinators. Does this evidence support the professor's claimthat fewer than 88 % of college students are procrastinators? Use a 0.02 level of significance.Step 2 of 3: Compute the value of the test statistic. Round your answer to two decimal places.

The question is about hypo. testing Given : Popl. prop. of students who identify themselves as…

Answered: believes that th 272 college student-…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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40 people are randomly sent to walk one of four trails. The time (in minutes) they spend completing each trail is recorded in the table below. (a) Test to see if the times needed to complete a trail vary. Use a 0.05 significance level. (b) Test each pair (A/B, A/C, A/D, B/C, B/D, C/D) to see which trails have a statistically significant difference. Indicate your p-value for each comparison, and when the effect is statistically significant (use 0.05 as your significance level), declare which trail of the two takes more time to complete. Trail A - 30, 33, 41, 27, 36, 31, 37, 40, 29, 35 Trail B - 27, 33, 38, 41, 40, 38, 35, 44, 41, 39 Trail C - 25, 34, 41, 39, 32, 30, 36, 35, 27, 33 Trail D - 41, 39, 46, 37, 40, 42, 50, 42, 50, 33, 47, 43
An LED light bulb manufacturer claims that the average lifespan of its 60-watt LED light bulbs is 27,000 hours. A corporate watchdog group is suspicious of the company's claim and thinks that the true average lifespan of the 60- watt LED light bulbs produced by the company may be less than the advertised 27,000 hours. The group collected and tested a random sample of 211 light bulbs and found the average lifespan of the sample was 26,941 hours. Use the p-value method to test the hypothesis that the mean lifespan of this brand of 60-watt LED light bulb is less than 27,000 hours, using a = 0.1. Assume the standard deviation of the lifespan of all such light bulbs is known to be 370 hours. State the null and alternative hypothesis for this test. Ho: ? H₁: ? Determine if this test is left-tailed, right-tailed, or two- tailed. right-tailed two-tailed left-tailed Should the standard normal (z) distribution or Student's (t) distribution be used for this test? The Student's t distribution…
Suppose that in a random selection of 100100 colored candies, 2323% of them are blue. The candy company claims that the percentage of blue candies is equal to 2525%. Use a 0.100.10 significance level to test that claim.
It is believed that 11% of all Americans are left-handed. A college needs to know how many left-handed desks to place in the big lecture halls being constructed on its campus. In a random sample of 120 students of its 12124 students, 15 were left-handed. Does this provide enough evidence to show that students at this college have a higher percentage of left-handers than the general American population? Use a 10% level of significance.
A student wants to see if the number of times a book has been checked out of the library in the past year and the number of pages in the book are related. She guesses that the number of times a book has been checked out of the library in the past year will be a predictor of the number of pages it has. She randomly sampled 15 books from the library, test her claim at a 0.05 level of significance. number of times checked out number of pages 13 223 45 350 49 377 30 371 3 343 7 280 17 218 7 265 20 382 23 287 1 313 30 388 20 358 2 311 40 421 The correlation coefficient: r= (round to 3 decimal places) The equation y=a+bx is: (round to 3 decimal places) y=+ x The hypotheses are: H0:ρ=0H0:ρ=0 (no linear relationship)HA:ρ≠0HA:ρ≠0 (linear relationship) (claim) Since αα is 0.05 the critical value is -2.16 and 2.16 The test value is: (round to 3 decimal places) The p-value is: (round to 3 decimal places) The decision is to reject H0H0 do not reject…
A marriage counselor has traditionally seen that the proportion p of all married couples for whom her communication program can prevent divorce is 77%. After making some recent changes, the marriage counselor now claims that her program can prevent divorce in more than 77% of married couples. In a random sample of 250 married couples who completed her program, 194 of them stayed together. Based on this sample, is there enough evidence to support the marriage counselor's claim at the 0.10 level of significance? Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places. (If necessary, consult a list of formulas.) (a) State the null hypothesis H and the alternative hypothesis H₁. H₁:0 H₁ :0 (b) Determine the type of test statistic to use. (Choose one) (c) Find the value of the test statistic. (Round to three or more decimal places.) 0 (d) Find the p-value. (Round to three or more decimal places.) 0 (e) Is there enough…
A survey of 2255 randomly selected US adults found that 51% said they know all or most of their neighbors. Does this provide evidence that more than half of US adults know most or all of their neighbors? Use 5% significance level.
A marriage counselor has traditionally seen that the proportion p of all married couples for whom her communication program can prevent divorce is 78%. After making some recent changes, the marriage counselor now claims that her program can prevent divorce in more than 78% of married couples. In a random sample of 240 married couples who completed her program, 189 of them stayed together. Based on this sample, is there enough evidence to support the marriage counselor’s claim at the 0.10 level of significance?Perform a one-tailed test. Then complete the parts below.
The General Social Survey is an annual survey given to about 1500 U.S. adults selected at random. A recent survey contained the question "How important to your life is having a fulfilling job?" Of the 267 college graduates surveyed, 106 chose the response "Very important." Of the 113 people surveyed whose highest level of education was high school or less, 59 chose the response "Very important." Based on these data, can we conclude, at the 0.05 level of significance, that there is a difference between the proportion p1 of all U.S. college graduates who would answer "Very important" and the proportion p2 of all U.S. adults whose highest level of education was high school or less who would answer "Very important"?Perform a two-tailed test. Then complete the parts below.Carry your intermediate computations to three or more decimal places and round your answers as specified in the parts below. (If necessary, consult a list of formulas.) A. Find the value of the test statistic and round to…
The dataset "nurses" is a random sample of 1,000 cases from “Health Care Provider Credential Data” from Washington State Open Data Portal. In the sample, there are 418 CNA's and 278 of the CNA's have expired credentials. Use the statistics from the nurses dataset to answer the following question: "With 90% confidence, what percent of all CNA's on Washington State's healthcare provider list are expired?"

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