If the test statistic is 1.95 on the Z distribution at a 3% significancelevel for a right-sided test, what is the conclusion?O Not enough information to make a conclusion.O Reject the null hypothesis.O Fail to reject the null hypothesis.3!!SAMSUNG

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Answered: If the test statistic is 1.95 on the Z…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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In a study of 819 randomly selected medical malpractice lawsuits, it was found that 473 of them were dropped or dismissed. Use a 0.01 significance level to test the claim that most medical malpractice lawsuits are dropped or dismissed. Which of the following is the hypothesis test to be conducted? ОА. Но: р30.5 H;: p> 0.5 ОС. Но: р0.5 H1: p= 0.5 OF. Ho: p= 0.5 ОЕ. Но: р-0.5 H1: p#0.5 H1: p<0.5 What is the test statistic? (Round to two decimal places as needed.) What is the P-value? P-value = (Round to three decimal places as needed.)
K In a study of 799 randomly selected medical malpractice lawsuits, it was found that 505 of them were dropped or dismissed. Use a 0.01 significance level to test the claim that most medical malpractice lawsuits are dropped or dismissed. What is the conclusion about the null hypothesis? OA. Fail to reject the null hypothesis because the P-value is greater than the significance level, a. OB. Reject the null hypothesis because the P-value is less than or equal to the significance level, a. OC. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, α. OD. Reject the null hypothesis because the P-value is greater than the significance level, a. What is the final conclusion? OA. There is sufficient evidence to support the claim that most medical malpractice lawsuits are dropped or dismissed. OB. There is not sufficient evidence to warrant rejection of the claim that most medical malpractice lawsuits are dropped pr dismissed. OC. There is…
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Births A random sample of 860 births in New York State included 426 boys. Use a 0.05 significance level to test the claim that 51.2% of newborn babies are boys. Do the results support the belief that 51.2% of newborn babies are boys?
B. Identify the test statistic Z=___ C. Identify the P-value. P-value=___ D. What is the conclusion based on the hypothesis test? The P-value is (greater than/less than) the significance level of α=0.01,so (reject/ fail to reject) the null hypothesis. There is (suffiecient/ insufficient) evidence to support the claim that the proportion of people over 55 who dream in black and white is greater than the proportion for those under 25. Test the claim by constructing an appropriate confidence interval. The 90% confidence interval is ___<( p1-p2)<___ E. Because the confidence interval limits (do not include/include) 0, it appears that the two proportions are (equal/not equal) Because the confidence interval limits include (only negative/ only positive/ negative and positive) values, it appears that the proportion of people over 55 who dream in black and white is (greater than/less than/ not significantly different from) the proportion for those under 25. F. An explanation…
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The table below includes results from polygraph (lie detector) experiments conducted by researchers. In each case, it was known if the subjected lied or did not lie, so the table indicates when the polygraph test was correct. Use a 0.05 significance level to test the claim that whether a subject lies is independent of the polygraph test indication. Do the results suggest that polygraphs are effective in distinguishing between truth and lies? E Click the icon to view the table. Determine the null and alternative hypotheses. O A. Ho: Polygraph testing is accurate. H1: Polygraph testing is not accurate. O B. Ho: Whether a subject lies is not independent of the polygraph test indication. H,: Whether a subject lies is independent of the polygraph test indication. O C. Ho: Polygraph testing is not accurate. H1: Polygraph testing is accurate. VD. Ho: Whether a subject lies is independent of the polygraph test indication. H,: Whether a subject lies is not independent of the polygraph test…
Conduct the hypothesis test and provide the test statistic and the critical value, and state the conclusion. K A person randomly selected 100 checks and recorded the cents portions of those checks. The table below lists those cents portions categorized according to the indicated values. Use a 0.05 significance level to test the claim that the four categories are equally likely. The person expected that many checks for whole dollar amounts would result in a disproportionately high frequency for the first category, but do the results support that expectation? D 0-24 30 Cents portion of check 25-49 24 Number Click here to view the chi-square distribution table. The test statistic is (Round to three decimal paces as needed.) 50-74 19 75-99 27
Suppose that in a random selection of 100 colored candies, 23% of them are blue. The candy company claims that the percentage of blue candies is equal to 29%. Use a 0.05 significance level to test that claim. Identify the null and alternative hypotheses for this test. Choose the correct answer below. O A. Ho: p=0.29 H1: p>0.29 O B. Ho: p#0.29 H1:p=0.29 O C. Ho: p=0.29 H1:p#0.29 OD. Ho: p=0.29 H1:p<0.29 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is . (Round to two decimal places as needed.) Identify the P-value for this hypothesis test. The P-value for this hypothesis test is (Round to three decimal places as needed.) Identify the conclusion for this hypothesis test. O A. Reject Ho. There is sufficient evidence to warrant rejection of the claim that the percentage of blue candies is equal to 29% O B. Fail to reject Ho. There is sufficient evidence to warrant rejection of the claim that the percentage of blue candies is equal to 29%
Test the claim that the proportion of men who own cats is smaller than the proportion of women who own cats at the .025 significance level. The null and alternative hypothesis would be: Ho MMF Ho: PM = PF H₁: MMF O H₁: PM > PF O The test is: two-tailed right-tailed O The test statistic is: Based on a sample of 60 men, 25% owned cats Based on a sample of 40 women, 40% owned cats The p-value is: Ho: M = μF H₁: UM
A social scientist sampled 140 people and classified them according to income level and whether or not they played the lottery (LOTTO) in the last month. The sample information is reported below. Is it reasonable to conclude that playing the lottery is related to income level? Use the .05 significance level. INCOME LOW MIDDLE HIGH TOTAL PLAYED 46 48 21 115 DID NOT PLAY 14 12 19 45 TOTAL 60 60 40 140 a. State the null hypothesis and the alternate hypothesis.b. What is the decision rule?c. Determine the value of chi-square.d. Interpret the results

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If the test statistic is 1.95 on the Z distribution at a 3% significance level for a right-sided test, what is the conclusion? O Not enough information to make a conclusion. O Reject the null hypothesis. O Fail to reject the null hypothesis.