**Chi-square Distribution Table**This table displays critical values of the Chi-square distribution for different degrees of freedom and significance levels. The table is used to determine the critical value of a Chi-square statistic for hypothesis testing. Here's how to interpret the table:- **Degrees of Freedom (df):** This is the first column, showing the different degrees of freedom for each row. It ranges from 1 to 10 in this table.- **Area to the Right of the Critical Value:** These are the columns labeled with the percentages 0.995, 0.99, 0.975, 0.95, 0.90, and 0.10. Each column corresponds to a significance level or probability threshold (α).**Values:**- For 1 degree of freedom: critical values range from 0.004 at 0.95 level to 2.706 at 0.10 level.- For 2 degrees of freedom: critical values range from 0.020 at 0.99 level to 4.605 at 0.10 level.- For 3 degrees of freedom: critical values range from 0.072 at 0.995 level to 6.251 at 0.10 level.- ...- For 10 degrees of freedom: critical values range from 2.156 at 0.995 level to 15.987 at 0.10 level.The values in the table indicate the cutoff point for the Chi-square statistic: if the calculated statistic is greater than the critical value, the null hypothesis may be rejected at the chosen significance level. Conduct the hypothesis test and provide the test statistic and the critical value, and state the conclusion.A person randomly selected 100 checks and recorded the cents portions of those checks. The table below lists those cents portions categorized according to the indicated values. Use a 0.05 significance level to test the claim that the four categories are equally likely. The person expected that many checks for whole dollar amounts would result in a disproportionately high frequency for the first category, but do the results support that expectation?| Cents portion of check | 0-24 | 25-49 | 50-74 | 75-99 ||------------------------|------|-------|-------|-------|| Number | 30 | 24 | 19 | 27 |Click here to view the chi-square distribution table.The test statistic is □ (Round to three decimal places as needed.)

The formula for the chi-square test statistic is given as,

Answered: Conduct the hypothesis test and provide…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The average house has 15 paintings on its walls. Is the mean larger for houses owned by teachers? The data show the results of a survey of 16 teachers who were asked how many paintings they have in their houses. Assume that the distribution of the population is normal. 18, 15, 17, 14, 16, 17, 18, 15, 15, 14, 14, 14, 15, 15, 16, 18 What can be concluded at the a = 0.05 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Но: Select an answer v H1: Select an answer v c. The test statistic ? v = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? va f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusion is that ... O The data suggest the population mean is not significantly more than 15 at a = 0.05, so there is sufficient evidence to conclude that the population mean number of paintings that are in…
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A survey was conducted that asked 1013 people how many books they had read in the past year. Results indicated that x=10.3 books and s=16.6books. Construct a 90% confidence interval for the mean number of books people read. Interpret the interval. Construct a 90% confidence interval for the mean number of books people read and interpret the result. Select the correct choice below and fill in the answer boxes to complete your choice. (Use ascending order. Round to two decimal places as needed.) A. There is a 90% probability that the true mean number of books read is between ___ and ____ B. There is 90% confidence that the population mean number of books read is between ___ and ____. C. If repeated samples are taken, 90% of them will have a sample mean between ___ and ___.
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A survey was conducted that asked 963 people how many books they had read in the past year. Results indicated that x=14.7 books and s=17.8 books. Construct a 90% confidence interval for the mean number of books people read. Interpret the interval.Construct a 90% confidence interval for the mean number of books people read and interpret the result. Select the correct choice below and fill in the answer boxes to complete your choice.(Use ascending order. Round to two decimal places as needed.)A. If repeated samples are taken, 90% of them will have a sample mean between ___ and ____ B. There is a 90% probability that the true mean number of books read is between ____ and ___ C. There is a 90% confidence that the population mean number of books read is between ___ and ___

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