B. Identify the test statistic.z=___C. Identify the P-value.P-value=___ D. What is the conclusion based on the hypothesis test? The P-value is (greater than/ less than) the significance level ofα=0.05, so (reject/ fail to reject) the null hypothesis. There (suffiecient/ is not sufficient) evidence to warrant rejection of the claim that women and men have equal success in challenging calls. Test the claim by constructing an appropriate confidence interval.The 95% confidence interval is___<(p1-p2)<____. E. What is the conclusion based on the confidence interval?Because the confidence interval limits (include/ do not include) 0, there (does/ does not) appear to be a significant difference between the two proportions. There (is sufficient/ is not sufficient) evidence to warrant rejection of the claim that men and women have equal success in challenging calls. F. Based on the results, does it appear that men and women may have equal success in challenging calls?The confidence interval suggests that there is a significant difference or The confidence interval suggests that there is no significant difference or There is not enough information to reach a conclusion. Since an instant replay system for tennis was introduced at a major tournament, men challenged 1427 referee calls, with the result that 426 of the calls were overturned. Women challenged 780 referee calls, and 230 of the calls were overturmed. Use a0.01 significance level to test the claim that men and women have equal success in challenging calls. Complete parts (a) through (c) below.a. Test the claim using a hypothesis test.Consider the first sample to be the sample of male tennis players who challenged referee calls and the second sample to be the sample of female tennis players who challenged referee calls. What are the null and alternative hypotheses for thehypothesis test?OA Ho: PP2H: P P2OE Ho: P *P2H: P = P2OF. Ho: P = P2H: P P2

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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B. Identify the test statistic.

z=___

C. Identify the P-value.

P-value=___

D. What is the conclusion based on the hypothesis test?

The P-value is (greater than/ less than) the significance level of

α=0.05, so (reject/ fail to reject) the null hypothesis. There (suffiecient/ is not sufficient) evidence to warrant rejection of the claim that women and men have equal success in challenging calls.

Test the claim by constructing an appropriate confidence interval.

The 95% confidence interval is___<(p1-p2)<____.

E. What is the conclusion based on the confidence interval?

Because the confidence interval limits (include/ do not include) 0, there (does/ does not) appear to be a significant difference between the two proportions. There (is sufficient/ is not sufficient) evidence to warrant rejection of the claim that men and women have equal success in challenging calls.

F. Based on the results, does it appear that men and women may have equal success in challenging calls?

The confidence interval suggests that there is a significant difference or The confidence interval suggests that there is no significant difference or There is not enough information to reach a conclusion.

Since an instant replay system for tennis was introduced at a major tournament, men challenged 1427 referee calls, with the result that 426 of the calls were overturned. Women challenged 780 referee calls, and 230 of the calls were overturmed. Use a
0.01 significance level to test the claim that men and women have equal success in challenging calls. Complete parts (a) through (c) below.
a. Test the claim using a hypothesis test.
Consider the first sample to be the sample of male tennis players who challenged referee calls and the second sample to be the sample of female tennis players who challenged referee calls. What are the null and alternative hypotheses for the
hypothesis test?
OA Ho: PP2
H: P <P2
OB. Ho: P 2 P2
H: P P2
OC. Ho: P SP2
H: P P2
OD. Ho: P = P2
H: P > P2
OE Ho: P *P2
H: P = P2
OF. Ho: P = P2
H: P P2

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