The null and alternative hypothesis would be: Но:р — 0.55 Но: р — 2.2 Но:р — 0.55 Но: и — Ho:P 0.55 Ho:H 2.2 Но: д — 2.2 Но:р — 0.55 Hі:р> 0.55 Hi:д + 2.2 Hі:р+0.55 Ні:> 2.2 Hi:д < 2.2 Ні:р < 0.55 The test is: two-tailed left-tailed right-tailed Based on a sample of 60 people, the sample mean GPA was 2.23 with a standard deviation of 0.02 The p-value is: (to 2 decimals) The significance level is: (to 2 decimals) Based on this we: Reject the null hypothesis O Fail to reject the null hypothesis
The null and alternative hypothesis would be: Но:р — 0.55 Но: р — 2.2 Но:р — 0.55 Но: и — Ho:P 0.55 Ho:H 2.2 Но: д — 2.2 Но:р — 0.55 Hі:р> 0.55 Hi:д + 2.2 Hі:р+0.55 Ні:> 2.2 Hi:д < 2.2 Ні:р < 0.55 The test is: two-tailed left-tailed right-tailed Based on a sample of 60 people, the sample mean GPA was 2.23 with a standard deviation of 0.02 The p-value is: (to 2 decimals) The significance level is: (to 2 decimals) Based on this we: Reject the null hypothesis O Fail to reject the null hypothesis
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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