Suppose that UIC financial aid alots a textbook stipend by claiming that the average textbook at UICbookstore costs $ 93. You want to test whether the average cost is different from this value.a) The null and alternative hypothesis in symbols would be:O Ho:p = 93H1:p + 93O Ho:µ = 93H1:µ > 93O Ho:p = 93H:р> 93Ο Η : μ 93H1:µ + 93O Ho: H = 93H1:µ < 93O Ho:p = 93H1:p < 93%3Db) The null hypothesis in words would be:The average price of textbooks in a sample is $ 93The average price of all textbooks from the store is different from $ 93.The average price of all textbooks from the store is less than $ 93.The average price of all textbooks from the store is greater than $ 93.O The average price of all textbooks from the store is $ 93O The proportion of all textbooks from the store that are less than 93 is equal to 50%c) Based on a sample of 11 textbooks at the store, you find an average of 91.17 and a standard deviation of15.6.The 97 % confidence interval is: 90.99 < µ < 91.35Based on the provided interval, we:O Accept the null hypothesisReject the null hypothesisO Fail to reject the null hypothesis

Answered: Suppose that UIC financial aid alots a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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An investigation was carried out to study the relationship between speed (ft/sec) and stride rate (number of steps taken/sec) among female marathon runners. Resulting summary quantities includedn = 11, E(speed) = 205.5, E(speed)2 = 3884.08, E(rate) = 35.15, E(rate)2 = 112.691, and E(speed)(rate) = 660.136. (a) Calculate the equation of the least squares line that you would use to predict stride rate from speed. (Round all numerical values to four decimal places.) (b) Calculate the equation of the least squares line that you would use to predict speed from stride rate. (Round all numerical values to four decimal places.) (c) Calculate the coefficient of determination for the regression of stride rate on speed of part (a) and for the regression of speed on stride rate of part (b). (Round your answers to three decimal places.) for part (a) for part (b)
(2) Sdr= 1 x=. V1-x2
6. Find the relative error if is approximated to 0-667.
10 veterans who suffer from PTSD are tested before and after taking an anti-anxiety medication thought to reduce PTSD symptoms. How do I report my findings in APA format? Before condition (M=52, SD= 13.4, SE=4.228) After condition (M=43, SD=13.4, SE=4.243) t(9)=1.581, p >0.05, d=0.500.
a b Absolute standard deviation = Coefficient of variation = y = 1.20 (+0.02) x 10-8-3.60(±0.2) × 10-⁹ x Result = Absolute standard deviation = Coefficient of variation = C Result = d y=90.95 (±0.08) - 89.40(±0.06) +0.200(+0.004) Absolute standard deviation == Coefficient of variation = Result = ± y= y = 0.0040 (+0.0005) x 10.28 (+0.02) × 395(+1) Result = ± Absolute standard deviation = Coefficient of variation = % 329(+0.03) x 10-14 1.47 (+0.04) x 10-16 % % H % ±
5. Bone mineral density (BMD) is a measure of bone strength. It is defined as the ratio of bone mass to the cross- sectional area of the bone that is scanned, and it is expressed in units of grams per square centimeter (g/cm²). Recent studies suggest that peak BMD in women is achieved between ages 15 and 40, and BMD declines after age 45. Decreased BMD is associated with increased risk of bone fracture. In a recent study, the impact of regular physical exercise on women in differing stages of BMD development was examined. A simple random sample of 59 women between the ages of 41 and 45 and with no major health problems were enrolled in the study. The women were classified into one of the two following groups, based on their level of exercise activity. • Sedentary: minimal participation in physical exercise in the past three years (This group contained 31 women.) • Walkers: walk at an aerobic pace at least 135 minutes per week during the past three years (This group contained 28 women.)…
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84 None 3t у" - зу'— 4у %3 е"variationof parameters |
The desired distance for Flextronchip customers is 0.4 mm between two adjacent pins. Any deviation from this value causes interference. The process of handling complaints costs the firm at approximately $30.00 per chip. The engineers of the firm expect the average customer will be likely to complain when the distance is off target by at least 0.0002 mm. At the factory, the adjustment can be made at a cost of $1.40, which includes the labor to make the adjustment and additional testing. Required: 1. What is the value of k, the cost coefficient, in the Taguchi quality loss function (QLF) based on the above data? 2. Based on a Taguchi quality loss function (QLF), what should the tolerance be before an adjustment is made at the factory? 3. Based on your answer to (requirement 2) above, what are the specification limits (upper and lower) for the production of the product in question? Complete this question by entering your answers in the tabs below. Required 2 Required 3 What is the value…
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