If a force is applied perpendicular to the radius of a rotating wheel, how is the torque calculated? T = TX F T = Fsin(0) ○ T = F/T ○ T=T/F If a beam is in equilibrium, which of the following must be true about the sum of the torques acting on it? The sum of the torques must be zero. The sum of the torques must be equal to the force times the distance. The sum of the torques must be equal to the sum of the forces. The sum of the torques must be equal to the force divided by the distance.

Glencoe Physics: Principles and Problems, Student Edition
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Chapter8: Rotational Motion
Section: Chapter Questions
Problem 82A
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I need help with this problem and an explanation for the solution described below. (University Physics 1: Torque and Statics)

If a force is applied perpendicular to the radius of a rotating wheel, how is the torque calculated?
T = TX F
T = Fsin(0)
○ T = F/T
○ T=T/F
Transcribed Image Text:If a force is applied perpendicular to the radius of a rotating wheel, how is the torque calculated? T = TX F T = Fsin(0) ○ T = F/T ○ T=T/F
If a beam is in equilibrium, which of the following must be true about the sum of the torques acting on it?
The sum of the torques must be zero.
The sum of the torques must be equal to the force times the distance.
The sum of the torques must be equal to the sum of the forces.
The sum of the torques must be equal to the force divided by the distance.
Transcribed Image Text:If a beam is in equilibrium, which of the following must be true about the sum of the torques acting on it? The sum of the torques must be zero. The sum of the torques must be equal to the force times the distance. The sum of the torques must be equal to the sum of the forces. The sum of the torques must be equal to the force divided by the distance.
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