If a force is applied perpendicular to the radius of a rotating wheel, how is the torque calculated? T = TX F T = Fsin(0) ○ T = F/T ○ T=T/F If a beam is in equilibrium, which of the following must be true about the sum of the torques acting on it? The sum of the torques must be zero. The sum of the torques must be equal to the force times the distance. The sum of the torques must be equal to the sum of the forces. The sum of the torques must be equal to the force divided by the distance.
If a force is applied perpendicular to the radius of a rotating wheel, how is the torque calculated? T = TX F T = Fsin(0) ○ T = F/T ○ T=T/F If a beam is in equilibrium, which of the following must be true about the sum of the torques acting on it? The sum of the torques must be zero. The sum of the torques must be equal to the force times the distance. The sum of the torques must be equal to the sum of the forces. The sum of the torques must be equal to the force divided by the distance.
Glencoe Physics: Principles and Problems, Student Edition
1st Edition
ISBN:9780078807213
Author:Paul W. Zitzewitz
Publisher:Paul W. Zitzewitz
Chapter8: Rotational Motion
Section: Chapter Questions
Problem 82A
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