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This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part. Tutorial Exercise Spiderman, whose mass is 79.0 kg, is dangling on the free end of a L = 12.9-m-long rope, the other end of which is fixed to a tree limb above. By repeatedly bending at the waist, he is able to get the rope in motion, eventually getting it to swing enough that he can reach a ledge when the rope makes a 61.1° angle with the vertical. How much work was done by the gravitational force on Spiderman in this maneuver? Part 1 of 4 - Conceptualize The force of the Earth on the man is fairly large and tends to slow his upward motion. Considering the mass involved and the value of g, we estimate that gravity should do hundreds, possibly thousands of joules of negative work on him. L ↑ Ꮎ Part 2 of 4 - Categorize He swings through several or many cycles, each going farther than the last. Gravity does positive work on him in each downswing and negative work in each upswing. We can use the definition of work by a constant force between the original starting point and the final endpoint. Part 3 of 4 - Analyze The work done is W = F. Ar, where the gravitational force on Spiderman is F g = -mgj = 79 79 kg g)(−9.80 m/s²)³ = -774.2 -774 N. He travels through net displacement given by the following. ΔΙ = L sin 61.1° ↑ + L1 4(1 - cos 61.1 = 12.9 12.9 m sin 61.1 Part 4 of 4 - Analyze Thus the work done by gravity is W = F. Ar Submit = -774 ĵN) · ( 11.30 -5162.58 X 61.1 61.1 % + 12.9 12.9 m)( 1 cos 61.1 61.1 ° îm + 6.67 ĵ m = Your response is off by a multiple of ten. x 10³] = -5162580 X Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. kJ. Skip (you cannot come back).

This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part. Tutorial Exercise Spiderman, whose mass is 79.0 kg, is dangling on the free end of a L = 12.9-m-long rope, the other end of which is fixed to a tree limb above. By repeatedly bending at the waist, he is able to get the rope in motion, eventually getting it to swing enough that he can reach a ledge when the rope makes a 61.1° angle with the vertical. How much work was done by the gravitational force on Spiderman in this maneuver? Part 1 of 4 - Conceptualize The force of the Earth on the man is fairly large and tends to slow his upward motion. Considering the mass involved and the value of g, we estimate that gravity should do hundreds, possibly thousands of joules of negative work on him. L ↑ Ꮎ Part 2 of 4 - Categorize He swings through several or many cycles, each going farther than the last. Gravity does positive work on him in each downswing and negative work in each upswing. We can use the definition of work by a constant force between the original starting point and the final endpoint. Part 3 of 4 - Analyze The work done is W = F. Ar, where the gravitational force on Spiderman is F g = -mgj = 79 79 kg g)(−9.80 m/s²)³ = -774.2 -774 N. He travels through net displacement given by the following. ΔΙ = L sin 61.1° ↑ + L1 4(1 - cos 61.1 = 12.9 12.9 m sin 61.1 Part 4 of 4 - Analyze Thus the work done by gravity is W = F. Ar Submit = -774 ĵN) · ( 11.30 -5162.58 X 61.1 61.1 % + 12.9 12.9 m)( 1 cos 61.1 61.1 ° îm + 6.67 ĵ m = Your response is off by a multiple of ten. x 10³] = -5162580 X Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. kJ. Skip (you cannot come back).

Physics for Scientists and Engineers: Foundations and Connections
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter5: Newton's Laws Of Motion
Section: Chapter Questions
Problem 35PQ: A black widow spider hangs motionless from a web that extends vertically from the ceiling above. If...
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This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part. Tutorial Exercise Spiderman, whose mass is 79.0 kg, is dangling on the free end of a L = 12.9-m-long rope, the other end of which is fixed to a tree limb above. By repeatedly bending at the waist, he is able to get the rope in motion, eventually getting it to swing enough that he can reach a ledge when the rope makes a 61.1° angle with the vertical. How much work was done by the gravitational force on Spiderman in this maneuver? Part 1 of 4 - Conceptualize The force of the Earth on the man is fairly large and tends to slow his upward motion. Considering the mass involved and the value of g, we estimate that gravity should do hundreds, possibly thousands of joules of negative work on him. L ↑ Ꮎ
Transcribed Image Text:This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part. Tutorial Exercise Spiderman, whose mass is 79.0 kg, is dangling on the free end of a L = 12.9-m-long rope, the other end of which is fixed to a tree limb above. By repeatedly bending at the waist, he is able to get the rope in motion, eventually getting it to swing enough that he can reach a ledge when the rope makes a 61.1° angle with the vertical. How much work was done by the gravitational force on Spiderman in this maneuver? Part 1 of 4 - Conceptualize The force of the Earth on the man is fairly large and tends to slow his upward motion. Considering the mass involved and the value of g, we estimate that gravity should do hundreds, possibly thousands of joules of negative work on him. L ↑ Ꮎ
Part 2 of 4 - Categorize He swings through several or many cycles, each going farther than the last. Gravity does positive work on him in each downswing and negative work in each upswing. We can use the definition of work by a constant force between the original starting point and the final endpoint. Part 3 of 4 - Analyze The work done is W = F. Ar, where the gravitational force on Spiderman is F g = -mgj = 79 79 kg g)(−9.80 m/s²)³ = -774.2 -774 N. He travels through net displacement given by the following. ΔΙ = L sin 61.1° ↑ + L1 4(1 - cos 61.1 = 12.9 12.9 m sin 61.1 Part 4 of 4 - Analyze Thus the work done by gravity is W = F. Ar Submit = -774 ĵN) · ( 11.30 -5162.58 X 61.1 61.1 % + 12.9 12.9 m)( 1 cos 61.1 61.1 ° îm + 6.67 ĵ m = Your response is off by a multiple of ten. x 10³] = -5162580 X Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. kJ. Skip (you cannot come back).
Transcribed Image Text:Part 2 of 4 - Categorize He swings through several or many cycles, each going farther than the last. Gravity does positive work on him in each downswing and negative work in each upswing. We can use the definition of work by a constant force between the original starting point and the final endpoint. Part 3 of 4 - Analyze The work done is W = F. Ar, where the gravitational force on Spiderman is F g = -mgj = 79 79 kg g)(−9.80 m/s²)³ = -774.2 -774 N. He travels through net displacement given by the following. ΔΙ = L sin 61.1° ↑ + L1 4(1 - cos 61.1 = 12.9 12.9 m sin 61.1 Part 4 of 4 - Analyze Thus the work done by gravity is W = F. Ar Submit = -774 ĵN) · ( 11.30 -5162.58 X 61.1 61.1 % + 12.9 12.9 m)( 1 cos 61.1 61.1 ° îm + 6.67 ĵ m = Your response is off by a multiple of ten. x 10³] = -5162580 X Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. kJ. Skip (you cannot come back).
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