This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part. Tutorial Exercise Spiderman, whose mass is 79.0 kg, is dangling on the free end of a L = 12.9-m-long rope, the other end of which is fixed to a tree limb above. By repeatedly bending at the waist, he is able to get the rope in motion, eventually getting it to swing enough that he can reach a ledge when the rope makes a 61.1° angle with the vertical. How much work was done by the gravitational force on Spiderman in this maneuver? Part 1 of 4 - Conceptualize The force of the Earth on the man is fairly large and tends to slow his upward motion. Considering the mass involved and the value of g, we estimate that gravity should do hundreds, possibly thousands of joules of negative work on him. L ↑ Ꮎ Part 2 of 4 - Categorize He swings through several or many cycles, each going farther than the last. Gravity does positive work on him in each downswing and negative work in each upswing. We can use the definition of work by a constant force between the original starting point and the final endpoint. Part 3 of 4 - Analyze The work done is W = F. Ar, where the gravitational force on Spiderman is F g = -mgj = 79 79 kg g)(−9.80 m/s²)³ = -774.2 -774 N. He travels through net displacement given by the following. ΔΙ = L sin 61.1° ↑ + L1 4(1 - cos 61.1 = 12.9 12.9 m sin 61.1 Part 4 of 4 - Analyze Thus the work done by gravity is W = F. Ar Submit = -774 ĵN) · ( 11.30 -5162.58 X 61.1 61.1 % + 12.9 12.9 m)( 1 cos 61.1 61.1 ° îm + 6.67 ĵ m = Your response is off by a multiple of ten. x 10³] = -5162580 X Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. kJ. Skip (you cannot come back).
This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part. Tutorial Exercise Spiderman, whose mass is 79.0 kg, is dangling on the free end of a L = 12.9-m-long rope, the other end of which is fixed to a tree limb above. By repeatedly bending at the waist, he is able to get the rope in motion, eventually getting it to swing enough that he can reach a ledge when the rope makes a 61.1° angle with the vertical. How much work was done by the gravitational force on Spiderman in this maneuver? Part 1 of 4 - Conceptualize The force of the Earth on the man is fairly large and tends to slow his upward motion. Considering the mass involved and the value of g, we estimate that gravity should do hundreds, possibly thousands of joules of negative work on him. L ↑ Ꮎ Part 2 of 4 - Categorize He swings through several or many cycles, each going farther than the last. Gravity does positive work on him in each downswing and negative work in each upswing. We can use the definition of work by a constant force between the original starting point and the final endpoint. Part 3 of 4 - Analyze The work done is W = F. Ar, where the gravitational force on Spiderman is F g = -mgj = 79 79 kg g)(−9.80 m/s²)³ = -774.2 -774 N. He travels through net displacement given by the following. ΔΙ = L sin 61.1° ↑ + L1 4(1 - cos 61.1 = 12.9 12.9 m sin 61.1 Part 4 of 4 - Analyze Thus the work done by gravity is W = F. Ar Submit = -774 ĵN) · ( 11.30 -5162.58 X 61.1 61.1 % + 12.9 12.9 m)( 1 cos 61.1 61.1 ° îm + 6.67 ĵ m = Your response is off by a multiple of ten. x 10³] = -5162580 X Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. kJ. Skip (you cannot come back).
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the
skipped part.
Tutorial Exercise
Spiderman, whose mass is 79.0 kg, is dangling on the free end of a L = 12.9-m-long rope, the other end of which is fixed to a tree limb above. By repeatedly bending at the waist, he is able
to get the rope in motion, eventually getting it to swing enough that he can reach a ledge when the rope makes a 61.1° angle with the vertical. How much work was done by the gravitational
force on Spiderman in this maneuver?
Part 1 of 4 - Conceptualize
The force of the Earth on the man is fairly large and tends to slow his upward motion. Considering the mass involved and the value of g, we estimate that gravity should do hundreds,
possibly thousands of joules of negative work on him.
L
↑
Ꮎ
![Part 2 of 4 - Categorize
He swings through several or many cycles, each going farther than the last. Gravity does positive work on him in each downswing and negative work in each upswing. We can use the
definition of work by a constant force between the original starting point and the final endpoint.
Part 3 of 4 - Analyze
The work done is W = F. Ar, where the gravitational force on Spiderman is
F
g
=
-mgj
=
79
79 kg
g)(−9.80 m/s²)³ =
-774.2
-774 N.
He travels through net displacement given by the following.
ΔΙ
= L sin 61.1° ↑ + L1
4(1
-
cos 61.1
=
12.9
12.9 m sin 61.1
Part 4 of 4 - Analyze
Thus the work done by gravity is
W = F. Ar
Submit
=
-774
ĵN) · (
11.30
-5162.58 X
61.1
61.1 % +
12.9
12.9 m)(
1
cos 61.1
61.1
°
îm + 6.67
ĵ m
= Your response is off by a multiple of ten. x 10³] =
-5162580 X
Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. kJ.
Skip (you cannot come back).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8d473413-bcea-4706-8a6c-0dae0f6f8353%2Fc7834dab-c900-4031-bf27-22ba0b93364d%2F7eo0xb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Part 2 of 4 - Categorize
He swings through several or many cycles, each going farther than the last. Gravity does positive work on him in each downswing and negative work in each upswing. We can use the
definition of work by a constant force between the original starting point and the final endpoint.
Part 3 of 4 - Analyze
The work done is W = F. Ar, where the gravitational force on Spiderman is
F
g
=
-mgj
=
79
79 kg
g)(−9.80 m/s²)³ =
-774.2
-774 N.
He travels through net displacement given by the following.
ΔΙ
= L sin 61.1° ↑ + L1
4(1
-
cos 61.1
=
12.9
12.9 m sin 61.1
Part 4 of 4 - Analyze
Thus the work done by gravity is
W = F. Ar
Submit
=
-774
ĵN) · (
11.30
-5162.58 X
61.1
61.1 % +
12.9
12.9 m)(
1
cos 61.1
61.1
°
îm + 6.67
ĵ m
= Your response is off by a multiple of ten. x 10³] =
-5162580 X
Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. kJ.
Skip (you cannot come back).
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