Don't use chat A force of 2.8 N acts on a 24 kg body initially at rest. Compute the work done by the force in (a) the first, (b) the second, and (c) thethird seconds and (d) the instantaneous power due to the force at the end of the third second.(a) Number iUnits(b) Number iUnits(c) Number iUnits(d) Number iUnits=<>

Step 1:The acceleration produced:F=ma2.8 = 24*aa = 0.11667m/s2 a.In the first 1st the distance moved…

Answered: A force of 2.8 N acts on a 24 kg body…

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter7: Work And Kinetic Energy

Section: Chapter Questions

Problem 54P: A 5.0-kg box has an acceleration of 2.0m/s2 when it is pulled by a horizontal force across a surface...

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Similar questions

A particle of mass 2.0 kg moves under the influence of the force F(x)=(5x2=7x)N . Suppose a frictional force also acts on the particle. If the particle’s speed when it starts at x=4.0 m is 0.0 m/s and when it arrives at x=4.0 m is 9.0 m/s, how much work is done on it by the frictional force between x=4.0 m and x=4.0 m?
An electron in a television tube is accelerated uniformly from rest to a speed of 8.4107 m/s over a distance of 2.5 cm. What is the power delivered to the electron at the instant that its displacement is 1.0 cm?
A person in good physical condition can put out 100 W of useful power for several hours at a stretch, perhaps by pedaling a mechanism that drives an electric generator. Neglecting any problems of generator efficiency and practical considerations such as resting time: (a) How many people ‘would it take to nm a 4.O0-kW electric clothes dryer? (b) How many people would it take to replace a large electric power plant that generates 800 MW?
A mouse of mass 200 g falls 100 m down a vertical mine shaft and lands at the bottom with a speed of 8.0 m/s. During its fall, how much work is done on the mouse by air resistance?
The surface of the preceding problem is modified so that the coefficient of kinetic friction is decreased. The same horizontal force is applied to the crate, and after being pushed 8.0 m, its speed is 5.0 m/s. How much work is now done by the force of friction? Assume that the crate starts at rest.
Give an example of a situation in which there is a force and a displacement, but the force does no work. Explain why it does no work.
A cart is pulled a distance D on a flat, horizontal surface by a constant farce F that acts at an angle with the horizontal direction. The other forces on the object during this time are gravity (Fw) , normal forces (FN1) and (FN2) , and rolling frictions Fr1 and Fr2 , as shown below What is the work done by each force?
Check Your Understanding Repeat Example 8.10 when the particle’s mechanical energy is +0.25 J.
Check Your Understanding Find the work done by the same force in Example 7.4 over a cubic path, y=(0.25m-2)x3 , between the same points A=(0,0) and B=(2m,2m) .
Repeat the preceding problem, but this time, suppose that the work done by air resistance cannot be ignored. Let the work done by the air resistance when the skier goes from A to B along the given hilly path be —2000 J. The work done by air resistance is negative since the air resistance acts in the opposite direction to the displacement. Supposing the mass of the skier is 50 kg, what is the speed of the skier at point B ?
A 500-kg dragster accelerates from rest to a final speed of 110 m/s in 400 m (about a quarter of a mile) and encounters an average frictional force of 1200 N. What is its average power output in watts and horsepower if this takes 7.30s?
Give an example of something we think of as work in everyday circumstances that is not work in the scientific sense. Is energy transferred or changed in form in your example? If so, explain how this is accomplished without doing work.

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