If 80.5 g of KBr are dissolved in 400.0 g of water at 25.0 °C in an insulated container, a temperature change is observed. The AH of solution of KBr is 19.9 kJ/ mol. Assuming that the specific heat of the solution is 4.184 J/(g°C), and that no heat is gained or lost by the container, what will be the fınal temperature of the solution?

Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter12: Thermodynamic Processes And Thermochemistry
Section: Chapter Questions
Problem 29P
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**Thermochemistry Problem: Calculating Final Temperature**

**Scenario:**
A certain amount of potassium bromide (KBr), precisely 80.5 grams, is dissolved in 400.0 grams of water at an initial temperature of 25.0 °C. The process is carried out in an insulated container, ensuring no heat exchange with the surroundings.

**Given Data:**
- Molarity of the enthalpy change for the dissolution of KBr (\(ΔH_{\text{solution}}\)): 19.9 kJ/mol.
- Specific heat capacity of the solution: 4.184 J/(g°C).
- No heat is gained or lost by the container.

**Objective:**
Determine the final temperature of the solution after the dissolution process.

**Instructions:**
- Carefully compute the heat exchanged during the dissolution of KBr and its effect on the temperature of the water.
- Utilize the specific heat capacity to calculate the temperature change, considering the combined mass of water and KBr.

**Understanding the Process:**
When KBr dissolves in water, it absorbs or releases heat, causing the solution's temperature to change. This example teaches key concepts in thermochemistry, including heat exchange, enthalpy changes, and specific heat calculations.

**Practical Application:**
Completing this problem requires calculation skills and understanding of thermodynamic principles, essential for studies in chemistry and related sciences.
Transcribed Image Text:**Thermochemistry Problem: Calculating Final Temperature** **Scenario:** A certain amount of potassium bromide (KBr), precisely 80.5 grams, is dissolved in 400.0 grams of water at an initial temperature of 25.0 °C. The process is carried out in an insulated container, ensuring no heat exchange with the surroundings. **Given Data:** - Molarity of the enthalpy change for the dissolution of KBr (\(ΔH_{\text{solution}}\)): 19.9 kJ/mol. - Specific heat capacity of the solution: 4.184 J/(g°C). - No heat is gained or lost by the container. **Objective:** Determine the final temperature of the solution after the dissolution process. **Instructions:** - Carefully compute the heat exchanged during the dissolution of KBr and its effect on the temperature of the water. - Utilize the specific heat capacity to calculate the temperature change, considering the combined mass of water and KBr. **Understanding the Process:** When KBr dissolves in water, it absorbs or releases heat, causing the solution's temperature to change. This example teaches key concepts in thermochemistry, including heat exchange, enthalpy changes, and specific heat calculations. **Practical Application:** Completing this problem requires calculation skills and understanding of thermodynamic principles, essential for studies in chemistry and related sciences.
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