If a student wants to make 225.0 mL of a 17.65M stock solution of ZnCl 2, how many grams of solid, anhydrous zinc chloride do they need to use? 837 g 21.8 g 541 g 34.3 g 19.1 g
1) If a student wants to make 225.0 mL of a 17.65M stock solution of ZnCl 2, how many grams of solid, anhydrous zinc chloride do they need to use?
837 g
21.8 g
541 g
34.3 g
19.1 g
2) When 93.25 grams of fictional compound X is added to water to make 534.3 grams of solution, the temperature decreases from 26.12 °C to 2.26 °C. What is the heat of solution for compound X given that the molar mass of compound X is 80.89 g/mol? Assume the specific heat capacity of the solution is 4.18 J/g°C.
53.28 kJ/mol
-46.22 kJ/mol
46.22 kJ/mol
12.31 kJ/mol
-53.28 kJ/mol
3)In the lab, you used 2.0 mM FD&C Yellow Dye No. 6 solution. How much solid dye, molar mass 452.36 g/mol, should be dissolved to make 5.40 liters of 9.35 mM FD&C Yellow Dye No. 6 solution? Hint, 2.0 mM is 0.0020 M.
22.84 g
50.49 g
41.10 g
111.6 g
0.04378 g
4) What is the experimental molar mass (that is, calculated from the data given and not taken from the periodic table) of magnesium if 0.0155 grams of magnesium generates 15.40 mL of hydrogen at 19.4 °C with a hydrogen partial pressure of 751.4 torr? Note that the partial pressure of water vapor has already been subtracted from the total pressure.
23.6 g/mol
26.5 g/mol
26.4 g/mol
20.5 g/mol
24.4 g/mol
5) A flask stoppered to a volume of 125. mL is heated from 19.19 °C to 60.00 °C. If the intial pressure in the flask is 777.6 torr, what is the final pressure in the flask?
886 torr
660. torr
752 torr
973 torr
493 torr
6) According to the balanced chemical question below, how many grams of Be 3N 2 can be formed from 6.77 moles of Be? Assume an excess of nitrogen gas. The molar mass of beryllium nitride (Be 3N 2) is 55.06 g/mol.
3 Be (s) + N 2 (g) ? Be 3N 2 (s)
0.391 g
75.7 g
805 g
373 g
124 g
7) What is the molality of a solution made by dissolving 13.5 grams of MnCl 2 in 380 grams of water?
27.8 m
0.565 m
0.0245 m
0.0142 m
0.282 m
8) A student reacts 17.7 grams of ZnCl 2 (MW=136.315g/mol) with 34.0 mL of 4.50M KOH. How many grams of solid product (MW = 99.424 g/mol) are formed?
0.131 g
12.9 g
10.3 g
5.08 g
7.61 g
9) If a student wants to make 225.0 mL of a 17.65M stock solution of ZnCl 2, how many grams of solid, anhydrous zinc chloride do they need to use?
837 g
21.8 g
541 g
34.3 g
19.1 g
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