I think I totally get how to draw lewis. S02 is puzzling. The third row does not need to obey the octet rule .  See my fork in the road decision as i completed the step where I dumped two electrons into the center. If I then create just one double bond, the central atom has a positive charge of one. It makes more sense to me to drop two double bonds and then the central atom has no charge and neither do the Oxygen's. I know the answer is just one double bond, but it does not make sense. Video on YouTube states that sulfur should have an Octet , But I have been taught that we don't have to have octets after the second row.   Am i missing some general rule?   My supposed to try to get octets on the third row too?

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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I think I totally get how to draw lewis. S02 is puzzling. The third row does not need to obey the octet rule .  See my fork in the road decision as i completed the step where I dumped two electrons into the center. If I then create just one double bond, the central atom has a positive charge of one. It makes more sense to me to drop two double bonds and then the central atom has no charge and neither do the Oxygen's. I know the answer is just one double bond, but it does not make sense. Video on YouTube states that sulfur should have an Octet , But I have been taught that we don't have to have octets after the second row.   Am i missing some general rule?   My supposed to try to get octets on the third row too? 

**Lewis Structure of SO₂**

The diagram illustrates the Lewis structure for sulfur dioxide (SO₂).

1. **Initial Structure:**
   - The structure shows two oxygen atoms single-bonded to a sulfur atom: \( O - S - O \).
   - Each oxygen atom is depicted with six valence electrons, shown as dots, and is indicated to carry a formal charge of -1.
   - The sulfur atom, placed in the center, is shown with four valence electrons and carries a formal charge of +2.

2. **Volume Calculation:**
   - For sulfur (S): Valence electrons = 6
   - For each oxygen (O): Valence electrons = 6
   - Total valence electrons: 18
   - Used in bonds: 6
   - Electrons left: 12

3. **Charge Neutralization Attempt:**
   - A revised structure is shown where sulfur forms a double bond with one oxygen, reducing the formal charge on that oxygen to zero. The other oxygen still has a single bond.

4. **Final Structure:**
   - To achieve zero formal charge on all atoms, the structure adjusts to show sulfur forming double bonds with both oxygen atoms: \( O = S = O \).

**Note:** This adjustment helps visualize how formal charges can be minimized in the Lewis structure to reflect a more accurate depiction of the molecule.
Transcribed Image Text:**Lewis Structure of SO₂** The diagram illustrates the Lewis structure for sulfur dioxide (SO₂). 1. **Initial Structure:** - The structure shows two oxygen atoms single-bonded to a sulfur atom: \( O - S - O \). - Each oxygen atom is depicted with six valence electrons, shown as dots, and is indicated to carry a formal charge of -1. - The sulfur atom, placed in the center, is shown with four valence electrons and carries a formal charge of +2. 2. **Volume Calculation:** - For sulfur (S): Valence electrons = 6 - For each oxygen (O): Valence electrons = 6 - Total valence electrons: 18 - Used in bonds: 6 - Electrons left: 12 3. **Charge Neutralization Attempt:** - A revised structure is shown where sulfur forms a double bond with one oxygen, reducing the formal charge on that oxygen to zero. The other oxygen still has a single bond. 4. **Final Structure:** - To achieve zero formal charge on all atoms, the structure adjusts to show sulfur forming double bonds with both oxygen atoms: \( O = S = O \). **Note:** This adjustment helps visualize how formal charges can be minimized in the Lewis structure to reflect a more accurate depiction of the molecule.
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