I think I totally get how to draw lewis. S02 is puzzling. The third row does not need to obey the octet rule . See my fork in the road decision as i completed the step where I dumped two electrons into the center. If I then create just one double bond, the central atom has a positive charge of one. It makes more sense to me to drop two double bonds and then the central atom has no charge and neither do the Oxygen's. I know the answer is just one double bond, but it does not make sense. Video on YouTube states that sulfur should have an Octet , But I have been taught that we don't have to have octets after the second row. Am i missing some general rule? My supposed to try to get octets on the third row too?
Formal Charges
Formal charges have an important role in organic chemistry since this concept helps us to know whether an atom in a molecule is neutral/bears a positive or negative charge. Even if some molecules are neutral, the atoms within that molecule need not be neutral atoms.
Polarity Of Water
In simple chemical terms, polarity refers to the separation of charges in a chemical species leading into formation of two polar ends which are positively charged end and negatively charged end. Polarity in any molecule occurs due to the differences in the electronegativities of the bonded atoms. Water, as we all know has two hydrogen atoms bonded to an oxygen atom. As oxygen is more electronegative than hydrogen thus, there exists polarity in the bonds which is why water is known as a polar solvent.
Valence Bond Theory Vbt
Valence bond theory (VBT) in simple terms explains how individual atomic orbitals with an unpaired electron each, come close to each other and overlap to form a molecular orbital giving a covalent bond. It gives a quantum mechanical approach to the formation of covalent bonds with the help of wavefunctions using attractive and repulsive energies when two atoms are brought from infinity to their internuclear distance.
I think I totally get how to draw lewis. S02 is puzzling. The third row does not need to obey the octet rule . See my fork in the road decision as i completed the step where I dumped two electrons into the center. If I then create just one double bond, the central atom has a positive charge of one. It makes more sense to me to drop two double bonds and then the central atom has no charge and neither do the Oxygen's. I know the answer is just one double bond, but it does not make sense. Video on YouTube states that sulfur should have an Octet , But I have been taught that we don't have to have octets after the second row. Am i missing some general rule? My supposed to try to get octets on the third row too?

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