How many mL of HCI, 0.1 M, will you need to prepare 0.700 L of HCL, 0.025 M?Student A and Studentwere analyzing the initial set up of the first problem.Step 1: Identify and label knowns and unknown•KnownUnknownM (initial) = 0.1 MV(initial) = ? mLM (final ) = 0.025 MV (final) = 0.700 LStep 2: Write the base equation for dilutionM(1) x V(i) = M (f) x V (f)Step 3: Solve for the unknown and substitute the values.V(i) = (0.025 M)(0.700 L) = 0.175 L0.1 MStudent B said, "The dilution equation works, because the number of particles of solute that is transferred does not change during the dilution."Student A replied, "That is correct. You only add water to dilute the solution, so the number of solute particles does not change."You consider Student A and Student B to be correct. O TrueO FalseDELL->$4&246.789.y uiWerfh | jk# M

How many mL of HCI, 0.1 M, will you need to prepare 0.700 L of HCL, 0.025 M? Student A and Student B were analyzing the initial set up of the first problem. Step 1: Identify and label knowns and unknown •Known Unknown M (initial) = 0.1 M V(initial) = ? mL M (final ) = 0.025 M V (final) = 0.700 L %3! Step 2: Write the base equation for dilution M() x V() = M (f) x V (f) Step 3: Solve for the unknown and substitute the values. V() = (0.025 M)(0.700 L) = 0.175 L 0.1 M Student B said, "The dilution equation works, because the number of particles of solute that is transferred does not change during the dilution." Student A replied, "That is correct. You only add water to dilute the solution, so the number of solute particles does not change." You consider Student A and Student B to be correct. O True O False

How many mL of HCI, 0.1 M, will you need to prepare 0.700 L of HCL, 0.025 M? Student A and Student B were analyzing the initial set up of the first problem. Step 1: Identify and label knowns and unknown •Known Unknown M (initial) = 0.1 M V(initial) = ? mL M (final ) = 0.025 M V (final) = 0.700 L %3! Step 2: Write the base equation for dilution M() x V() = M (f) x V (f) Step 3: Solve for the unknown and substitute the values. V() = (0.025 M)(0.700 L) = 0.175 L 0.1 M Student B said, "The dilution equation works, because the number of particles of solute that is transferred does not change during the dilution." Student A replied, "That is correct. You only add water to dilute the solution, so the number of solute particles does not change." You consider Student A and Student B to be correct. O True O False

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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