1. How many mL of a 0.02 M Mg(OH)₂ solution are required to neutralize 40.0 mL of 0.05 M HNO3 solution? 0.02=m Mg(OH)₂ = M (ml) = M (ml) 0.05 N (0.05 m) x = (40 ml) (0-02 M) 0.05x = 0.8 x=16mL 7 2. What was the initial pH of the HNO3 solution and the Mg(OH)₂ solution described in problem no. 1? Initial pH of HNO3

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N
1. How many mL of a 0.02 M Mg(OH)₂ solution are required to neutralize 40.0 mL of
0.05 M HNO3 solution?
0.05x=0.8
x= 16mL
7
M (ml) = M (ml)
0.02=m Mg(OH)₂ = 0.05 N
(0.05 m) x = (40 ml) (0-02M)
✓
2. What was the initial pH of the HNO3 solution and the Mg(OH)₂ solution described in
problem no. 1?
Initial pH of HNO3
Transcribed Image Text:N 1. How many mL of a 0.02 M Mg(OH)₂ solution are required to neutralize 40.0 mL of 0.05 M HNO3 solution? 0.05x=0.8 x= 16mL 7 M (ml) = M (ml) 0.02=m Mg(OH)₂ = 0.05 N (0.05 m) x = (40 ml) (0-02M) ✓ 2. What was the initial pH of the HNO3 solution and the Mg(OH)₂ solution described in problem no. 1? Initial pH of HNO3
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