[Kererences Calculate the sodium ion concentration when 60.0 mL of 2.0 M sodium carbonate is added to 40.0 mL of 1.3 M sodium bicarbonate. Assume that the volumes are additive. Concentration = M Suhmit Answer Visited Try Another Version 6 item attempts remaining

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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**Problem Statement:**

Calculate the sodium ion concentration when 60.0 mL of 2.0 M sodium carbonate is added to 40.0 mL of 1.3 M sodium bicarbonate. Assume that the volumes are additive.

**Input Area:**

Concentration = [_________] M

**Options:**

- Submit Answer
- Try Another Version

6 item attempts remaining

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This is an educational exercise for calculating the final concentration of sodium ions when two solutions are mixed together. Two solutions are being mixed: sodium carbonate (\(\text{Na}_2\text{CO}_3\)) and sodium bicarbonate (\(\text{NaHCO}_3\)).

**Steps to Solve:**

1. **Calculate the moles of sodium ions in each solution:**
   - Sodium carbonate provides two sodium ions per formula unit.
   - Sodium bicarbonate provides one sodium ion per formula unit.

2. **Find the total volume after mixing:**
   - Add the volumes of the two solutions.

3. **Use the formula for concentration:**
   - \[ C = \frac{\text{Total moles of sodium ions}}{\text{Total volume in liters}} \]

By solving this problem, students can practice calculating molarity in mixed solutions, reinforcing concepts of stoichiometry and solution chemistry.
Transcribed Image Text:**Problem Statement:** Calculate the sodium ion concentration when 60.0 mL of 2.0 M sodium carbonate is added to 40.0 mL of 1.3 M sodium bicarbonate. Assume that the volumes are additive. **Input Area:** Concentration = [_________] M **Options:** - Submit Answer - Try Another Version 6 item attempts remaining --- This is an educational exercise for calculating the final concentration of sodium ions when two solutions are mixed together. Two solutions are being mixed: sodium carbonate (\(\text{Na}_2\text{CO}_3\)) and sodium bicarbonate (\(\text{NaHCO}_3\)). **Steps to Solve:** 1. **Calculate the moles of sodium ions in each solution:** - Sodium carbonate provides two sodium ions per formula unit. - Sodium bicarbonate provides one sodium ion per formula unit. 2. **Find the total volume after mixing:** - Add the volumes of the two solutions. 3. **Use the formula for concentration:** - \[ C = \frac{\text{Total moles of sodium ions}}{\text{Total volume in liters}} \] By solving this problem, students can practice calculating molarity in mixed solutions, reinforcing concepts of stoichiometry and solution chemistry.
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