Procedure: 1. Prepare 50 mL of a 0.100 M solution of LiCl, 2. Using this stock solution, prepare a series of solutions (20 mL each) with the following concentrations: 0.0500 M, 0.0250 M., 0.0125 M., and 0.00625 M. The dilutions should leave-30 mL of the 0.100 M stock solution to finish the series. (Note that each solution in the series is ½ the concentration of the previous solution.) 3. Using the information in the tables below, plot conductivity (mS cm') vs. concentration (mol/L) using Excel (or other plotting software) and apply a linear regression analysis to the plot. 4. Repeat steps 1-3 for formic acid. LICI mS cm' 10.66 Formic Acid mol/L mol/L 0.10000 0.05000 ms cm 1.79 1.60 0.10000 7.75 0.05000 6.30 0.02500 1.50 0.02500 5.57 0.01250 1.45 0.01250 5.21 0.00625 1.43 0.00625 Questions: 1. Determine the mass of LiCI (42.394 g/mol) required for Step 1.

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Procedure:
1. Prepare 50 mL of a 0.100 M solution of LiCl.
2. Using this stock solution, prepare a series of solutions (20 mL each) with the following concentrations:
0.0500 M, 0.0250 M, 0.0125 M, and0.00625 M. The dilutions should leave ~30 mL of the 0.100 M
stock solution to finish the series.
(Note that each solution in the series is ½ the concentration of the previous solution.)
3. Using the information in the tables below, plot conductivity (mS cm') vs. concentration (mol/L) using Excel
(or other plotting software) and apply a linear regression analysis to the plot.
4. Repeat steps 1-3 for formic acid.
LICI
Formic Acid
ms cm
10.66
mol/L
0.10000
ms cm
1.79
1.60
mol/L
0.10000
7.75
0.05000
0.05000
6.30
0.02500
1.50
0.02500
5.57
0.01250
1.45
0.01250
5.21
0.00625
1.43
0.00625
Questions:
1. Determine the mass of LİCI (42.394 g/mol) required for Step l.
2. Show your calculations for the volume of 0.100 M LİCI required for each dilution in Step 2.
(HINT: dilution law: M¡Vi = M¿V2)
3. Submit your two clearly labeled plots (including their linear fits) from Excel (or other plotting
software). There is a short video on D2L on how to plot using Excel.
4. Which compound is the stronger electrolyte? What do you believe to be the major factor accounting for
the difference?
Transcribed Image Text:Solutions Procedure: 1. Prepare 50 mL of a 0.100 M solution of LiCl. 2. Using this stock solution, prepare a series of solutions (20 mL each) with the following concentrations: 0.0500 M, 0.0250 M, 0.0125 M, and0.00625 M. The dilutions should leave ~30 mL of the 0.100 M stock solution to finish the series. (Note that each solution in the series is ½ the concentration of the previous solution.) 3. Using the information in the tables below, plot conductivity (mS cm') vs. concentration (mol/L) using Excel (or other plotting software) and apply a linear regression analysis to the plot. 4. Repeat steps 1-3 for formic acid. LICI Formic Acid ms cm 10.66 mol/L 0.10000 ms cm 1.79 1.60 mol/L 0.10000 7.75 0.05000 0.05000 6.30 0.02500 1.50 0.02500 5.57 0.01250 1.45 0.01250 5.21 0.00625 1.43 0.00625 Questions: 1. Determine the mass of LİCI (42.394 g/mol) required for Step l. 2. Show your calculations for the volume of 0.100 M LİCI required for each dilution in Step 2. (HINT: dilution law: M¡Vi = M¿V2) 3. Submit your two clearly labeled plots (including their linear fits) from Excel (or other plotting software). There is a short video on D2L on how to plot using Excel. 4. Which compound is the stronger electrolyte? What do you believe to be the major factor accounting for the difference?
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