Ho : u = 424 H1 : µ # 424 %3D x = 445.3 %3D o = 115.4 = 99 0.05 %3D Standard Normal Distribution Table a. Calculate the test statistic. 0.00 Round to two decimal places if necessary b. Determine the critical value(s) for the hypothesis test. CURMIT OJESTION
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- Test a claim that the mean amount of carbon monoxide in the air in U.S. cities is less than 2.31 parts per million. It was found that the mean amount of carbon monoxide in the air for the random sample of 66 cities is 2.37 parts per million and the standard deviation is 2.11 parts per million. At α=0.05, can the claim be supported? Complete parts (a) through (e) below. Assume the population is normally distributed. (a) Identify the claim and state H0 and Ha. Which of the following correctly states H0 and Ha? The claim is the ( null) ( alternative) hypothesis (b) Use technology to find the critical value(s) and choose the graph that shows the rejection region (c) Find the standardized test statistic, t. (d) Decide whether to reject or fail to reject the null hypothesis. (e) Interpret the decision in the context of the original claim.〖 H〗_0 ∶p=0.70,〖 H〗_a ∶p≠0.70Sample size (n)= 150Sample proportion=0.75α= 0.05 a. Compute the test-statistic. Determine the critical value and draw the normal curve. Conclusion. Exercise C:A research conducted on a certain company last year showed that 25% of the employees would rather drink coffee than soft drinks during break time. The company has recently decided to give free coffee during break time. In the new research conducted this year, out of the 125 randomly sampled employees 28% said that they would rather drink coffee than soft drinks. At 0.05 level of significance, is there sufficient evidence to suggest that the coffee drinkers have increased since the company has decided to give free coffee during break time? Exercise D:Before the Mayweather vs Pacquiao's Fight of the Century, 75 % of the people in Manila said that they preferred boxing over basketball. After the fight, out of the 150 randomly . chosen people in Manila, 105 said they preferred boxing over…Test a claim that the mean amount of lead in the air in U.S. cities is less than 0.036 microgram per cubic meter. It was found that the mean amount of lead in the air for the random sample o 57 U.S. cities is 0.039 microgram per cubic meter and the standard deviation is 0.069 microgram per cubic meter. At α=0.10, can the claim be supported? Complete parts (a) through (e) below. Assume the population is normally distributed.
- Test a claim that the mean amount of lead in the air in U.S. cities is less than 0.036 microgram per cubic meter. It was found that the mean amount of lead in the air for the random sample of 57 U.S. cities is 0.039 microgram per cubic meter and the standard deviation is 0.067 microgram per cubic meter. At α=0.10, can the claim be supported? Complete parts (a) through (e) below. Assume the population is normally distributed. Question content area bottom Part 1 (a) Identify the claim and state H0 and Ha. H0: ▼ pp muμ sigma squaredσ2 sigmaσ ▼ not equals≠ greater than> less than or equals≤ less than< equals= greater than or equals≥ enter your response here Ha: ▼ muμ sigma squaredσ2 pp sigmaσ ▼ not equals≠ equals= greater than or equals≥ greater than> less than or equals≤ less than< enter your response here (Type integers or decimals. Do not round.) The claim is the ▼ null alternative…Test for Potassium (Normal Value: 3.5-5.5 mmol/L) Day Result 1 3.5 3.6 3 4.5 4 3.6 5 4.9 4.5 7 3.8 Mean Standard Deviation Coefficient of VariationTesting:H0:μ=15.5H0:μ=15.5H1:μ<15.5H1:μ<15.5Your sample consists of 27 subjects, with a mean of 14 and standard deviation of 3.26.Calculate the test statistic, rounded to 2 decimal places. t=
- PSingle Sign-On Error O Quiz: 7.4 Empirical Rule Practice x cture.com/courses/379654/quizzes/2037918/take T's Website Student Portal A Classes O Stephen Curry Tripl.. P Class Score Detail O 0.1573 G Image result for ma. O Submit Assignment E Marquis Dae Copy. Question 17 1 pts In a standardized test with a normal distribution of scores, the mean is 60 and the standard deviation is 10. Which score can be expected to occur most often? O 45 O 65 O 64 O 74 Submit Quiz Quiz saved at 11:41am 06Test a claim that the mean amount of carbon monoxide in the air in U.S. cities is less than 2.32 parts per million. It was found that the mean amount of carbon monoxide in the air for the random sample of 63 cities is 2.39 parts per million and the standard deviation is 2.11 parts per million. At α=0.05, can the claim be supported? Complete parts (a) through (e) below. Assume the population is normally distributed.Hypodermic needles are produced in a manufacturing process. The quality feature to be monitored is the outside diameter (in mm) for which the target value=0.8 is specified. We assume that the outside diameter is due to production-related variations Mμ, 02)- distributed. In the course of monitoring the process, a test random sample is taken from the ongoing production N=10 needles removed. The sample mean (arithmetic mean) is 0.827, which is the sample standard deviation (empirical standard deviation).s(x) = 0.05 a) Are the data compatible with the hypothesis that the target value0=0.8 is maintained on average in the overall production? Test this HO: με μό 1:06μ to the significance levela- 5%. The quantiles required for the test are included Rto determine. In your solution, indicate the command used for this. against b) How small or how large should the sample mean of a sample with a size of N=10 with the same sample standard deviation, so that the null hypothesis in part a) is…
- Test a claim that the mean amount of carbon monoxide in the air in U.S. cities is less than 2.33 parts per million. It was found that the mean amount of carbon monoxide in the air for the random sample of 64 cities is 2.38 parts per million and the standard deviation is 2.11 parts per million. At α=0.01, can the claim be supported? Complete parts (a) through (e) below. Assume the population is normally distributed. Question content area bottom Part 1 (a) Identify the claim and state H0 and Ha. Which of the following correctly states H0 and Ha? H0: ▼ sigmaσ muμ sigma squaredσ2 pp ▼ greater than or equals≥ not equals≠ equals= greater than> less than< less than or equals≤ enter your response here Ha: ▼ pp muμ sigmaσ sigma squaredσ2 ▼ greater than or equals≥ not equals≠ greater than> less than or equals≤ less than< equals= enter your response here (Type integers or decimals. Do not round.) The claim…Vitamin C in Fruits and Vegetables The amounts of vitamin C (in milligrams) for 100g (3.57 ounces) of various randomly selected fruits and vegetables are listed. Is there sufficient evidence to conclude that the standard deviation differs from 12mg? Use =α0.10 (a)State the hypotheses and identify the claim with the correct hypothesis. H0: H1: Is a claim or not a claim? Critical Values: 3.325, 16.919 Compute the test value. Round the answer to at least three decimal places. 7.9 16.3 12.8 13.0 32.2 28.1 34.4 46.4 53.0 15.4Test a claim that the mean amount of carbon monoxide in the air in U.S. cities is less than 2.33 parts per million. It was found that the mean amount of carbon monoxide in the air for the random sample of 66 cities is 2.38 parts per million and the standard deviation is 2.12 parts per million. At α=0.01, can the claim be supported? Complete parts (a) through (e) below. Assume the population is normally distributed.