Test for Potassium (Normal Value: 3.5-5.5 mmol/L)DayResult3.53.614.534.2.03.64.96.74.56.53.87.810MeanStandard DeviationCoefficient of Variation

We have given that, Day(x) :- 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 Results (f) :--3.5, 3.6, 4.5, 2.0, 3.6,…

Answered: Test for Potassium (Normal Value:…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Find the percent of the total area under the standard normal curve between the following z-scores Z= 0.6 and z= 1.2 Find the total percent of area between
H0 : =150.00 kPa H1 :>150.00 kPa b) α= 0.01; sample variance : 1300 (freq. table ) sample deviation : 36.0555 (freq. table ) Calculation of Data Mean of the results= = 6700/50 =134 Mid Range of the results= (217.32+46.32)/2= 131.82 Range = (217.32-46.32) = 171 Modal Class= Class 121-145 with the highest frequency of 15 Median of the sorted set of data = 132.25 Mode = there are not clear modes In the samples. Sample variance S o= 1300 Sample deviation: S =36.55
Use Table A to find the value z of a standard Normal variable that satisfies each of the given conditions. (Use the value of z from Table A that comes closest to satisfying the condition.) In each case, sketch a standard Normal curve with your value of z marked on the axis. Find the point z with 74% of the observations falling below it. Give your answer to two decimal places.
Demand for your product averages 20 units per day, with a standard deviation of 4. Your lead time is 5 days. (See attached) What should your reorder point be, if you want to have a 95% chance of not running out of products during the lead time? With this reorder level, how much safety stock do you have?
Find the area of the shaded region under the standard normal curve. Standard normal table E Click here to view the standard normal table. .00 .01 .02 .03 .04 .05 .06 .07 .08 .09 0.0 .5000 5040 .5080 .5120 .5160 5199 .5239 .5279 .5319 .5359 0.0 0,1 .5557 .5948 .5636 .6026 0.1 .5398 .5438 5478 .5517 .5596 .5675 .5714 .5753 z = 0.62 5793 .6179 0.2 .5832 5871 .5910 .5987 .6064 .6103 .6141 0.2 .6443 .6808 0.3 .6217 .6255 .6293 .6331 .6368 .6406 .6480 .6517 0.3 0.4 6700 .6554 .6591 .6628 .6664 .6736 .6772 .6844 .6879 0.4 The area of the shaded region is 7123 0.5 6915 6950 6985 7019 7054 .7088 .7157 7190 .7224 0.5 (Round to four decimal places as needed.) 7454 .7486 06 .7257 7291 7324 .7357 .7389 .7422 7517 7549 0.6 0.7 7580 7611 .7642 .7673 7704 .7734 .7764 7794 7823 7852 0.7 7910 8078 0.8 .7881 .7939 .7967 7995 .8023 .8051 .8106 .8133 0.8 .8264 .8340 0.9 0.9 .8159 .8186 .8212 .8238 .8289 .8315 .8365 .8389 1.0 .8413 .8438 .8461 .8485 .8508 .8531 .8554 .8577 .8599 .8621 1.0 1.1 .8643 .8665…
Identify the z-score corresponding to the indicated percentile. For the standard normal curve, find the z-score that corresponds to the third quartile. 0.77 -0.23 0.67 -0.67
normal distribution with a mean of u = 23.8 in, and a standard deviation of a = 1.1 in. These data are often used in the design of different Suppose that the sitting back-to-knee length for a group of adults has seats, including aircraft seats, train seats, theater seats, and classroom seats. Instead of using 0.05 for identifying significant values, use the criteria that a value x is significantly high if P(x or greater)50.01 and a value is significantly low if P(x or less) s0.01. Find the back-to-knee lengths separating significant values from those that are not significant. Using these criteria, is a back-to-knee length of 26.0 in. significantly high? Find the back-to-knee lengths separating significant values from those that are not significant. Back-to-knee lengths greater than in. and less than (Round to one decimal place as needed.) in. are not significant, and values outside that range are considered significant. Using these criteria, is a back-to-knee length of 26.0 in.…
Q/ In the vehicle speed test, the results are given in the table below: Find 1. Arithmetic mean 2. Standard deviation 3. Skew coefficient 4. Kurtosis coefficient * Speed range (km/hr Speed range (km/hr Frequency(fi) Speed range (km/hr Frequency(fi) Frequency(fi) 34-35.9 4 44-45.9 22 54-55.9 13 36-37.9 46-47.9 8 56-57.9 8 38-39.9 48-49.9 18 58-59.9 40-41.9 10 50-51.9 17 60-61.9 42-43.9 7 52-53.9 16 62-63.9
Find the approximate area of the shaded region . The graph depicts the standard normal deviation Z~N(0,1)
Find the percent of the total area under the standard normal curve between the following z-scores. z=-0.86 and z=0.86 The percent of the total area between z- -0.86 and z 0.86 is enter your response here %. (Round to the nearest integer.)
Test for Potassium (Normal Value: 3.5-5.5 mmol/L) Day Result 1 3.5 3.6 3 4.5 4 3.6 5 4.9 4.5 7 3.8 Mean Standard Deviation Coefficient of Variation
Find the area of the shaded region. The graph depicts the standard normal distribution with mean 0 and standard deviation 1. Click to view page 1 of the table. Click to view page 2 of the table. Standard normal distribution table (page 1) 7=065 .09 .08 .07 .06 .05 .04 .03 .02 .01 .00 The area of the shaded region is. Standard normal distribution table (page 2) -3.4 .0002 .0003 .0003 .0003 .0003 .0003 .0003 .0003 0003 .0003 3.4 - 3.3 - 3.2 - 3.1 - 3.0 - 2.9 .0003 .0004 .0004 .0004 .0004 .0004 .0004 .0005 .0005 .0005 -3.3 (Round to four decimal places as needed.) .0007 .0010 - 3.2 - 3.1 .0005 .0005 .0005 .0006 .0006 .0006 .0006 .0006 .0007 .0007 .0007 .0008 .0008 .0008 .0008 .0009 .0009 .0009 .0010 .0010 .0011 .0011 .0011 .0012 .0012 .0013 .0013 .0013 -3.0 .00 .01 .02 .03 .04 .05 .06 .07 .08 .09 - 2.9 - 2.8 - 2.7 .0014 .0014 .0015 .0015 .0016 .0016 .0017 .0018 .0018 .0019 0.0 5000 .5040 .5080 .5120 .5160 .5199 .5239 .5279 5319 5359 0.0 .0026 .0035 -2.8 .0019 .0020 .0021 .0021 .0022 .0023…

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Test for Potassium (Normal Value: 3.5-5.5 mmol/L) Day Result 3.5 3.6 1 4.5 3. 4. 2.0 3.6 4.9 6.7 4.5 6.5 3.8 7. 8. 9 10 Mean Standard Deviation Coefficient of Variation