Heights of 10 year old children, regardless of sex, closely follow a normal distribution with mean 54.8 inches and standard deviation 7 inches. For parts (a) through (c), enter your responses as a decimal with 2 decimal places. a at percentage of 10 year old children are more than 46.05 inches tall? hat percentage of 10 year old children are less than 59 inches tall? hat percentage of 10 year old children are between 46.05 and 59 inches tall? d) 74 % of 10 year old children are less than inches tall? (Do not round the final answer for d).)

Heights of 10 year old children, regardless of sex, closely follow a normal distribution with mean 54.8 inches and standard deviation 7 inches. For parts (a) through (c), enter your responses as a decimal with 2 decimal places. a at percentage of 10 year old children are more than 46.05 inches tall? hat percentage of 10 year old children are less than 59 inches tall? hat percentage of 10 year old children are between 46.05 and 59 inches tall? d) 74 % of 10 year old children are less than inches tall? (Do not round the final answer for d).)

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Frank measured the heights of the trees near his house. The heights (in feet) he recorded are 31, 41, 64, 107, 43, 32, 39, 41, 55, 39, 104, 53, 65. What is the range of tree height within one standard deviation of the mean? O 35 to 75 O 5 to 105 O 15 to 95 O 30 to 80 %23 M COST +1.71% nere to search F10 F11 F12 Prt Sc Insert Del F7 F8 F9 F5 F6 F4 Backspace 24 % 5 6 7 8 9
Jse the Empirical Rule. The mean speed of a sample of vehicles along a stretch of highway is 64 miles per hour, with a standard deviation of 4 miles per hour. Estimate the percent of vehicles whose speeds are between miles per hour and 72 miles per hour. (Assume the data set has a bell-shaped distribution.) Approximately % of vehicles travel between 56 miles per hour and 72 miles per hour.
suppose that peices of a gallon of mill at various stores in one town have amean of $3.75 with a stabdard deviation of $0.09 use chebyshev theourm what is the minimum percentage of stires that sell a gallon of milk for between $3.57 and $3.93 round your answer tk ine decimal place
open file attached for question
The coefficient of variation CV describes the standard deviation as a percent of the mean. Because it has no units, you can use the coefficient of variation to compare data with different units. Find the coefficient of variation for each sample data set. What can you conclude? Standard deviation CV = • 100% Mean E Click the icon to view the data sets. Data Table ..... CVneights = 71.2% (Round to the nearest tenth as needed.) Heights Weights 68 181 77 169 72 167 72 207 71 177 70 175 78 185 69 186 67 221 70 216 67 209 73 206
During an experiment, the following times (in seconds) were recorded. Find the mean. 6.3, 5.4, 6, 3.2, 5.4, 5.5 ... The mean is (Round to one decimal place as needed.) ...
The frequency distribution was obtained using a class width of 0.5 for data on cigarette tax rates. Use the frequency distribution to approximate the population mean and population standard deviation. Compare these results to the actual mean μ = $1.638 and standard deviation o = $1.052. Click the icon to view the frequency distribution for the tax rates. The population mean is $ (Round to three decimal places as needed.) book Get more help. C *** Frequency distribution of cigarette tax rates G Search or type URL Tax Rate 0.00-0.49 0.50-0.99 1.00-1.49 1.50-1.99 2.00-2.49 2.50-2.99 3.00-3.49 3.50-3.99 4.00-4.49 Print Frequency O 7 12 6 6 6 6 3 3 1 Done - X Clear all Check answer
What is the other name of Arithmetic Average? O a. Spread variability Ob. Mean O c. Median O d. Weighted mean
The coefficient of variation CV describes the standard deviation as a percent of the mean. Because it has no units, you can use the coefficient of variation to compare data with different units. Find the coefficient of variation for each sample data set. What can you conclude? Standard deviation CV = • 100% Mean E Click the icon to view the data sets. Data Table C/heights = 5.0 % (Round to the nearest tenth as needed.) Heights Weights CVweights =% (Round to the nearest tenth as needed.) 68 181 77 169 72 167 72 207 71 177 70 175 78 185 69 186 67 221 70 216 67 209 73 206
Find Geometric mean from the following distribution : х%3D4, 5, 6, 7, 8,9. f= 2, 3, 4, 3, 2, 1.
The IRS claims it takes an average of 3.7 hours to complete a 1040 tax form. Assume the time t the form is normally distributed with a standard deviation of 15 minutes or 0.25 hours. complete Use the Cumulative Z-Score Table to answer the following questions. Write your answer as a percent using 2 decimal places. What percent of people would you expect to complete the form in less than 3.45 hours? What percent of people would you expect to complete the form-in more than 3.45 hours? What percent of people would you expect to complete the form in less than 3.4 hours? What percent of people would you expect to complete the form in more than 3.4 hours? What percent of people would you expect to complete the form between 3.4 and 3.45 hours?
Which is NOT a correct statement about mean, median, standard deviation, or interquartile range? a. Mean is more affected by changes in extreme observations b. Median is less affected by changes in extreme observations c. Standard deviation is less affected by changes in extreme observations d. Interquartile range is less affected by changes in extreme observations