The frequency distribution was obtained using a class width of 0.5 for data on cigarette tax rates. Use the frequency distribution to approximate the population mean and population standard deviation. Compare these results to the actual mean u = $1.727 and standarddeviation o = S1.041.E Click the icon to view the frequency distribution for the tax rates.Frequency distribution of cigarette tax ratesThe population mean is $Tax Rate0.00-0.490.50-0.991.00-1,491.50-1.992.00-2.492.50-2.993.00-3.493.50-3.99Frequency D(Round to three decimal places as needed.)515The population standard deviation is S(Round to three decimal places as needed.)Compare these results to the values found using the actual data.O A. The grouped mean is slightly larger, while the grouped standard deviation is slightly smaller.O B. The grouped values are both slightly larger.O C. The grouped values are both slightly smaller.O D. The grouped mean is slightly smaller, while the grouped standard deviation is slightly larger.4.00–4.491PrintDone

Given , the frequency distribution, we need to find the population mean and population standard…

Answered: The frequency distribution was obtained…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Find the mean of the data summarized in the given frequency distribution. Compare the computed mean to the actual mean of 51.7 degrees. Low Temperature (o F) Frequency 40 - 44 45- 49 50 – 54 55 - 59 60 - 64 O 3 2 The mean of the frequency distribution is (Round to the nearest tenth as needed.) degrees. Which of the following best describes the relationship between the computed mean and the actual mean? O A. The computed mean is close to the actual mean because the difference between the means is less than 5% of the actual mean. O B. The computed mean is not close to the actual mean because the difference between the means is more than 5% of the actual mean. OC. The computed mean is close to the actual mean because the difference between the means is more than 5% of the actual mean. O D. The computed mean is not close to the actual mean because the difference between the means is less than 5% of the actual mean.
Explain if it is possible to obtain a negative value for SS (e.g. when calculating variability for something like temperature). MacBook Air
please show all steps using excel formulas
Find the mean of the data summarized in the given frequency distribution. Compare the computed mean to the actual mean of 51.6 miles per hour. Speed (miles per hour) Frequency 42 - 45 46 - 49 50 - 53 54 – 57 58 – 61 22 13 3 The mean of the frequency distribution is miles per hour. (Round to the nearest tenth as needed.)
find the mean of the data summarized in the given frequency distribution. Compare and computed mean to the actual mean of 51.9 miles per hour:speed (miles per hr) Frequency42-45 2146.49 1250-53 754-57 458-61 2The mean of the frequency is _____What is the relationship between the computed mean and the actual mean?
Find the mean of the data summarized in the given frequency distribution. Compare the computed mean to the actual mean of 55,8 degrees. Low Temperature (o F) Frequency 40 -44 45-40 50 -54 55-50 80-64 O 2 10 1 The mean of the frequency distribution is degrees. (Round to the nearest tenth as needed.)
Use the frequency distribution to create a histogram with single class values (a bar for 1, a bar for 2, etc.) that displays the data. Number of times fast food ordered number of students (frequency) 1 9 2 8 3 2 4 5 5 6 Total 30
Find the mean of the frequency distribution
Statistics Question
How hot does it get in Death Valley? The following data are taken from a study conducted by the National Park System, of which Death Valley is a unit. The ground temperatures (°F) were taken from May to November in the vicinity of Furnace Creek. Compute the mean, median, and mode for these ground temperatures. (Round your mean to four decimal places.) mean median mode 144 154 170 175 187 180 181 187 180 170 180 167 154 142 D
Use the frequency table that you constructed in question number 3 to find the percentile rank. What is the percentile rank of Age of 45 (Use a formula and show all calculations). Round up to two numbers after the decimal point in percentile rank.
Complete the table below. High Temperatures (°F) (Round to the nearest hundredth as needed.) Cumulative frequency Relative frequency Class Frequency, f Midpoint 18-28 18 23 0.05 18 29-39 43

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