=y 3 5
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Find the
The mean of the frequency distribution is degrees.
The given data is
Low Temperature | Frequency |
40-44 | 3 |
45-49 | 5 |
50-54 | 9 |
55-59 | 4 |
60-64 | 1 |
Step by step
Solved in 2 steps
- The following data represents the temperature of a town in degrees. DATA: Observation 1 2 3 4 5 6 7 8 9 DATA 5 0 -19 -7 37 -10 -9 46 57 What is the arithmetic mean? (round to the nearest hundredth; place your answer in the box below)TABLE 1.11 Ⓡ Twenty-five Starbucks customers are polled in a marketing survey and asked, "How often do you visit Starbucks in a typical week?" Table 1.11 lists the responses for these 25 customers. Construct a relative frequency histogram to describe the data. Number of Visits in a Typical Week for 25 Customers 5 6 8 4 6 5 ܗ ܟ ܗ ܗ 3 1655L 1465 7 6375A professor records the following final grades in one course. Construct a frequency table for the grades. A A A A B B B B C C C C D D A C B C C BD 4F F Complete the table. (Type an integer or decimal rounded to the nearest tenth as needed.) Grade Frequency Relative frequency Cumulative frequency A % 0
- Use the box and Whisker plot to answer the following Questions.Age of people who like Mint flavored Ice Cream.What is the Median Age of people who like Mint flavored Ice cream? A 30 B 90 C 50 D can’t tell from just this displayplease use sturge's formula to calculate class intervalRefer to the data set of body temperatures in degrees Fahrenheit given in the accompanying table and use software or a calculator to find the mean and median. Do the results support or contradict the common belief that the mean body temperature is 98.6°F? Click the icon for the body temperature data. The mean of the data set is °F. (Round to two decimal places as needed.) The median of the data set is °F. (Type an integer or a decimal. Do not round.) Do the results support or contradict the common belief that the mean body temperature is 98.6°F? O A. The results contradict the belief that the mean body temperature is 98.6°F because both the mean and the median are less than 98.6°F. B. The results are inconclusive because the median body temperature is not equal to 98.6°F while the mean is approximately equal to 98.6°F. C. The results are inconclusive because the mean body temperature is not equal to 98.6°F while the median is approximately equal to 98.6°F. O D. The results support the…
- On the right are raw test scores from a history test. a. Construct an ordered stem and leaf plot for the given data. b. Construct a grouped frequency table for these scores with intervals of 5, starting the first class at 55. c. Draw a histogram of the data. d. If a circle graph of the grouped data in (b) were drawn, how many degrees would be in the section representing the 55–59 interval? 56 65 75 89 91 61 76 73 76 78 77 74 83 81 86 87 82 85 85 83 83 99 96 96 98Construct one table that includes relative frequencies based on the frequency distributions shown below, then compare the amounts of tar in nonfiltered and filtered cigarettes. Do the cigarette filters appear to be effective? (Hint: The filters reduce the amount of tar ingested by the smoker.) Click the icon to view the frequency distributions. Complete the relative frequency table below. Relative Relative Frequency Frequency Tar (mg) (Nonfiltered) (Filtered) 4-8 % % % % % % % % % % 9-13 14-18 19-23 24-28 29-33 34-38 (Simplify your answers.) wan exa C Frequency Distributions Tar (mg) in Nonfiltered Cigarettes Frequency 14-18 19-23 24-28 29-33 34-38 8 N 2 1 -462 14 CID Tar (mg) in Filtered Cigarettes 4-8 9-13 14-18 19-23 Frequency 1 1 7 16 4 D - X k answer 85°F Clear OPThe table gives the frequency distribution for the final grades in a course. (Here A=4, B=3, C=2, D=1,F=0.) Determine the percentage of students who get a B or higher. Grade 0 1 2 3 4 Number of Occurrences 3 6 4 3 How could the answer be found? OA. Add the number of occurrences for each grade that is a B or higher. Then, divide by the number of grades. OB. Find the probability of each grade. Then, add them together to find the percent OC. Find the probability of each grade that is a B or higher. Then, find the average of those probabilities. OD. Find the probability of each grade. Then, add the probabilities for the grades that are a B or higher together to find the percent. The percentage of students who get a B or higher is
- Answer 18 and 18 only. Answer completely and typewritten only for upvote. Thank youConsider the following data: - 4 - 3 - 1 P(X = x) 0.2 0.1 0.2 0.1 0.4 Step 4 of 5: Find the value of P(X > -2). Round your answer to one decimal place.The ages (in years) and helghts (in inches) of all pitchers for a beseball team are listed. Find the coefficient of variation for each of the two data sets. Then compare the results. -Click the Icon to view the data sets. CV. %D Round to one decimal place as needed.)