Find the mean of the data summarized in the given frequency distribution. Compare the computed mean to the actual mean of 52.9 degrees. Low Temperature (o F) 40-44 45-49 50-54 55-59 60-64 3 Frequency 1 6 10 5 The mean of the frequency distribution is degrees. (Round to the nearest tenth as needed.)
Find the mean of the data summarized in the given frequency distribution. Compare the computed mean to the actual mean of 52.9 degrees. Low Temperature (o F) 40-44 45-49 50-54 55-59 60-64 3 Frequency 1 6 10 5 The mean of the frequency distribution is degrees. (Round to the nearest tenth as needed.)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![### Understanding Means in Frequency Distributions
#### Problem Statement
You are given a task to compute the mean of a frequency distribution and analyze its closeness to the actual mean.
#### Transcription:
- **The mean of the frequency distribution is [blank] miles per hour.**
- *(Round to the nearest tenth as needed.)*
#### Question:
Which of the following best describes the relationship between the computed mean and the actual mean?
1. **A.** The computed mean is close to the actual mean because the difference between the means is more than 5%.
2. **B.** The computed mean is close to the actual mean because the difference between the means is less than 5%.
3. **C.** The computed mean is not close to the actual mean because the difference between the means is less than 5%.
4. **D.** The computed mean is not close to the actual mean because the difference between the means is more than 5%.
#### Explanation:
- **Computed Mean vs. Actual Mean:** When evaluating statistical data, the mean (average) of a set of values is calculated to represent the central tendency. Comparing the computed mean to the actual mean helps determine accuracy.
- **Percent Difference:** The options explore whether the difference between the means is significant based on a 5% threshold.
For educational purposes, this assessment helps students understand statistical deviations and evaluate the accuracy of their calculations within a given context.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7207ec05-c570-45c5-9f93-6adc9f301e8e%2F3371af3b-bc80-478b-887a-f5debf43a18b%2Fl7600a_processed.png&w=3840&q=75)
Transcribed Image Text:### Understanding Means in Frequency Distributions
#### Problem Statement
You are given a task to compute the mean of a frequency distribution and analyze its closeness to the actual mean.
#### Transcription:
- **The mean of the frequency distribution is [blank] miles per hour.**
- *(Round to the nearest tenth as needed.)*
#### Question:
Which of the following best describes the relationship between the computed mean and the actual mean?
1. **A.** The computed mean is close to the actual mean because the difference between the means is more than 5%.
2. **B.** The computed mean is close to the actual mean because the difference between the means is less than 5%.
3. **C.** The computed mean is not close to the actual mean because the difference between the means is less than 5%.
4. **D.** The computed mean is not close to the actual mean because the difference between the means is more than 5%.
#### Explanation:
- **Computed Mean vs. Actual Mean:** When evaluating statistical data, the mean (average) of a set of values is calculated to represent the central tendency. Comparing the computed mean to the actual mean helps determine accuracy.
- **Percent Difference:** The options explore whether the difference between the means is significant based on a 5% threshold.
For educational purposes, this assessment helps students understand statistical deviations and evaluate the accuracy of their calculations within a given context.
Transcribed Image Text:**Problem Statement:**
Find the mean of the data summarized in the given frequency distribution. Compare the computed mean to the actual mean of 52.9 degrees.
**Frequency Distribution Table:**
| Low Temperature (°F) | 40 – 44 | 45 – 49 | 50 – 54 | 55 – 59 | 60 – 64 |
|----------------------|---------|---------|---------|---------|---------|
| Frequency | 1 | 6 | 10 | 5 | 3 |
**Instructions:**
The mean of the frequency distribution is ____ degrees. (Round to the nearest tenth as needed.)
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