Testing: H0:μ=15.5H0:μ=15.5 H1:μ<15.5H1:μ<15.5 Your sample consists of 27 subjects, with a mean of 14 and standard deviation of 3.26. Calculate the test statistic, rounded to 2 decimal places. t=
Inverse Normal Distribution
The method used for finding the corresponding z-critical value in a normal distribution using the known probability is said to be an inverse normal distribution. The inverse normal distribution is a continuous probability distribution with a family of two parameters.
Mean, Median, Mode
It is a descriptive summary of a data set. It can be defined by using some of the measures. The central tendencies do not provide information regarding individual data from the dataset. However, they give a summary of the data set. The central tendency or measure of central tendency is a central or typical value for a probability distribution.
Z-Scores
A z-score is a unit of measurement used in statistics to describe the position of a raw score in terms of its distance from the mean, measured with reference to standard deviation from the mean. Z-scores are useful in statistics because they allow comparison between two scores that belong to different normal distributions.
Testing:
H0:μ=15.5H0:μ=15.5
H1:μ<15.5H1:μ<15.5
Your sample consists of 27 subjects, with a
Calculate the test statistic, rounded to 2 decimal places.
![Test the claim that the proportion of people who own cats is larger than 90% at the 0.01
significance level.
The null and alternative hypothesis would be:
H2:µ < 0.9 Ho:µ > 0.9 Họ:p < 0.9 Họ:p = 0.9 Họ:p = 0.9 Họ:p > 0.9
H1:µ > 0.9 H:µ < 0.9 H1:p > 0.9 H1:H + 0.9 H1:p + 0.9 H1:p < 0.9
The test is:
two-tailed left-tailed right-tailed
Based on a sample of 600 people, 95% owned cats
The test statistic is:
(to 2 decimals)
The p-value is:
(to 2 decimals)
Based on this we:
O Reject the null hypothesis
O Fail to reject the null hypothesis](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fced1ea4e-957f-4838-a966-f554d33731c2%2Feabba838-01e4-421f-8c09-bba9563dd7e0%2Fvrpnl2t_processed.png&w=3840&q=75)
![Test the claim that the mean GPA of night students is larger than 2.9 at the 0.05 significance level.
The null and alternative hypothesis would be:
Но: р> 2.9 Но:р<0.725 Но:р — 0.725 Но: р < 2.9 Но:р — 2.9 Но:р2 0.725
H:4< 2.9 H:p > 0.725 H:p + 0.725 H:u > 2.9 H:p + 2.9 H:p < 0.725
The test is:
two-tailed left-tailed right-tailed
Based on a sample of 30 people, the sample mean GPA was 2.94 with a standard deviation of 0.04
The test statistic is:
(to 2 decimals)
The p-value is:
(to 2 decimals)
Based on this we:
Reject the null hypothesis
O Fail to reject the null hypothesis](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fced1ea4e-957f-4838-a966-f554d33731c2%2Feabba838-01e4-421f-8c09-bba9563dd7e0%2F6gude9_processed.png&w=3840&q=75)
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