What's the hypotheses for t-test?T-statistics?Critical values? The rejection region if test statistic falls in the rejection area and if to reject H0. Cooling down with a cold drink before exercise in the heat is believed to help an athlete perform. A researcher explored the difference between cooling down with an ice slurry (slushy) and with cold water. Ten male participants drank a flavoredice slurry and ran on a treadmill in a controlled hot and humid environment. Days later, the same participants drank cold water and ran on a treadmill in the same hot and humid environment. The table available below shows the times, inminutes, it took to fatique on the treadmill for both the ice slurry and the cold water. Preliminary data analyses indicate that use of a paired t-test is reasonable. At the 1% significance level, do the data provide sufficient evidence to concludethat, on average, cold water is less effective than ice slurry for optimizing athletic performance in the heat? Use the critical-value approach. (Note: The mean and standard deviation of the paired differences are - 4.8 minutes and 2.15minutes, respectively.)Click here to view the data. Click here to view a table of critical values of t. Let population 1 be the times to fatigue for cold water and let population 2 be the times to fatigue for ice slurry.Time to FatigueTSubjectCold WaterIce Slurry O4853283241474414927306.3844736388.455392730103235PrintDone df10.10t0.02510.0110.005df3.0786.31412.70631.8216.96563.6572.9202.3532.1.8864.3033.1829.92531.6384.5415.8411.5332.1322.7763.7474.6041.4762.0151.9431.8951.8601.8332.5712.4473.3653.1432.9982.8964.0323.70756.1.4406.71.4151.3972.3652.3063.4993.35578.89.1.3832.2622.8213.2509.101.3721.8122.2282.7643.1693.1063.05510111.3631.7962.2012.718111.3561.7822.1792.1602.145122.68112131.3501.3451.7711.7612.6502.6243.01213142.9771415161.3411.3371.7532.1312.6022.5832.5672.5522.5392.9472.92115161.7462.120171.3331.7402.1102.89817181.3302.8781.7341.7292.10118191.3282.0932.86119201.3251.7252.0862.5282.84520211.3231.7211.7172.0802.5182.8312.81921221.3212.0742.50822231.3191.7142.0692.5002.80723241.3181.7112.0642.4922.79724251.3161.7082.0602.4852.78725261.3151.7062.0562.4792.4732.4672.4622.7792627271.3142.0521.7031.7012.771282928291.3132.0482.7631.3111.6992.0452.756301.6972.0422.0402.0372.0351.3102.4572.75030311.3091.6962.4532.7443132331.3091.6942.4492.7382.7332,72832331.3081.6922.445341.3071.6912.0322.44134351.3061.6902.0302.4382.7242.7192.71535361.3061.6882.0282.43436371.3051.6872.0262.43137381.3041.6861.6852.0242.0232.4292.7122.70838391.3042.42639401.3031.6842.0212.4232.70440411.3032.0201.6831.6821.6812.4212.701411.3021.302422.0182.4182.69842432.0172.0152.4162.6952.69243441.3011.6802.414442.0142.013452.4122.4102.6902.6871.3011.6791.67945461.30046471.3001.6782.0122.4082.68547481.2991.6772.0112.4072.68248491.2991.6772.010 2.4052.68049df1o.10taest0.025t0.005df

Name: What's the hypotheses for t-test?T-statistics?Critical values? The rej
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: What's the hypotheses for t-test?T-statistics?Critical values? The rejection region if test statistic falls in the rejection area and if to reject H0. Cooling down with a cold drink before exercise in the heat is believed to help an athlete perform.

Answered: Image /qna-images/answer/ad14f45b-38a8-441f-9906-d499e670aaba.jpg

Math

Statistics

e slurry and ran on a treadmill in a controlled hot and humid environment. Days later, the same participants drank cold water and ran on a treadmill in the same hot and humid environment. The table available below shows the times, r inutes, it took to fatigue on the treadmill for both the ice slurry and the cold water. Preliminary data analyses indicate that use of a paired t-test is reasonable. At the 1% significance level, do the data provide sufficient evidence to concl at, on average, cold water is less effective than ice slurry for optimizing athletic performance in the heat? Use the critical-value approach. (Note: The mean and standard deviation of the paired differences are - 4.8 minutes and 2.15 minutes, respectively.) lick here to view the data, Click here to view a table of critical values oft Let population 1 be the times to fatigue for cold water and let population 2 be the times to fatigue for ice slurry. Time to Fatigue Subject Cold Water Ice Slurry 48 53 32 47 49 30 28 41 4. 41 6. 7 27 38 36 44 38 53 30 35 27 10 32 Print Done

e slurry and ran on a treadmill in a controlled hot and humid environment. Days later, the same participants drank cold water and ran on a treadmill in the same hot and humid environment. The table available below shows the times, r inutes, it took to fatigue on the treadmill for both the ice slurry and the cold water. Preliminary data analyses indicate that use of a paired t-test is reasonable. At the 1% significance level, do the data provide sufficient evidence to concl at, on average, cold water is less effective than ice slurry for optimizing athletic performance in the heat? Use the critical-value approach. (Note: The mean and standard deviation of the paired differences are - 4.8 minutes and 2.15 minutes, respectively.) lick here to view the data, Click here to view a table of critical values oft Let population 1 be the times to fatigue for cold water and let population 2 be the times to fatigue for ice slurry. Time to Fatigue Subject Cold Water Ice Slurry 48 53 32 47 49 30 28 41 4. 41 6. 7 27 38 36 44 38 53 30 35 27 10 32 Print Done

Big Ideas Math A Bridge To Success Algebra 1: Student Edition 2015

1st Edition

ISBN:9781680331141

Author:HOUGHTON MIFFLIN HARCOURT

Publisher:HOUGHTON MIFFLIN HARCOURT

Chapter4: Writing Linear Equations

Section: Chapter Questions

Problem 14CR

See similar textbooks

Related questions

Q: When it comes to casino games, the odds of winning at blackjack are better than the odds of winning…

A: The null hypothesis is, Ho: There is no association between the favorite game and passed in…

Q: True or False? H0 for an ANOVA test often states that all the population mean values from the…

A: Solution: The given statement is “H0 for an ANOVA test often states that all the population mean…

Q: In AÑOVA, when we want to "control for" variation in the response variable that is due to a factor…

A: Randomised block ANOVA; The aim is to minimize the variance among units within blocks relative to…

Q: Use technology to find the P- value for the hypothesis's test described below. The claim is that…

Q: Using the p-value method, should be rejected at the level of significance? Why or why not?

A: We performed t-test for difference between two means assuming equal variances in Excel. Test…

Q: An exterminator claims that no more than 10% of the homes he treats have termite problems within 1…

Q: Which best illustrates the distinction between statistical significance and practical importance?

A: Option 3 "In 50,000 births, the new vaccine reduced the incidence of infant mortality in Morrovia…

Q: If you want to reject the null hypothesis, which should be larger, the within groups or between…

A: We have given that a statement related to null hypothesis in case of F test.

Q: Conduct an independent - samples t-test to examine the difference between the mean ratings of the…

A: The objective of this question is to conduct an independent-samples t-test to examine the difference…

Q: Does cable video-on-demand (VOD) increase ad effectiveness? A study compared general TV and VOD…

A: Given : p^1= probability of Group 1 saying Yes=49223p^2= probability of Group 2 saying Yes=126237n1=…

Q: Using the z-table, the critical value for a left-tailed test with a significance level of 1% is…

Q: Find the critical value(s) and rejection region(s) for the indicated t-test, level of significance…

A: From the provided information, Sample size (n) = 9 Level of significance (α) = 0.10 The test is left…

Q: You have an SRS of 14 observations from a Normally distributed population. Use Table C to find the…

A: DF = n-1 = 14-1 = 13 Confidence Level = 99.5

Q: Test of independence between X and Y. Does it reject or not the null hypothesis if chi-squared test…

A: we know that when we do test for independence of variable we use chi square test statistics. And if…

Q: What does it mean for a test result to be statistically significant? Describe the relationship…

A: In Hypothesis testing either a claim could be rejected or it could be accepted. There are two types…

Q: Estimate the average weekly TV hours watched by students at this university with 99% confidence.…

A: Here, we have to obtain the 99% confidence interval for estimating the average weekly TV hours…

Q: The summary statistics are n=85, x=3.93, s=0.63. Use a 0.01 significance level to test the claim…

A: We have to complete hypothesis testing....

Q: Using the t-table, find the critical value for a left-tailed test with a significance level of 10%…

A: Sample size n=25Level of significance=0.10We have to find critical value for left tail test

Q: You are conducting a study to see if the proportion of voters who prefer Candidate A is…

A: P = proportion of voters who prefer candidate AClaim : p>0.81Test statistic : z = 2.845P value =…

Topic Video

Question

What's the hypotheses for t-test?

T-statistics?

Critical values?

The rejection region if test statistic falls in the rejection area and if to reject H₀.

Cooling down with a cold drink before exercise in the heat is believed to help an athlete perform. A researcher explored the difference between cooling down with an ice slurry (slushy) and with cold water. Ten male participants drank a flavored
ice slurry and ran on a treadmill in a controlled hot and humid environment. Days later, the same participants drank cold water and ran on a treadmill in the same hot and humid environment. The table available below shows the times, in
minutes, it took to fatique on the treadmill for both the ice slurry and the cold water. Preliminary data analyses indicate that use of a paired t-test is reasonable. At the 1% significance level, do the data provide sufficient evidence to conclude
that, on average, cold water is less effective than ice slurry for optimizing athletic performance in the heat? Use the critical-value approach. (Note: The mean and standard deviation of the paired differences are - 4.8 minutes and 2.15
minutes, respectively.)
Click here to view the data. Click here to view a table of critical values of t. Let population 1 be the times to fatigue for cold water and let population 2 be the times to fatigue for ice slurry.
Time to Fatigue
T
Subject
Cold Water
Ice Slurry O
48
53
28
32
41
47
4
41
49
27
30
6.
38
44
7
36
38
8.
45
53
9
27
30
10
32
35
Print
Done

df
10.10
t0.025
10.01
10.005
df
3.078
6.314
12.706
31.821
6.965
63.657
2.920
2.353
2.
1.886
4.303
3.182
9.925
3
1.638
4.541
5.841
1.533
2.132
2.776
3.747
4.604
1.476
2.015
1.943
1.895
1.860
1.833
2.571
2.447
3.365
3.143
2.998
2.896
4.032
3.707
5
6.
1.440
6.
7
1.415
1.397
2.365
2.306
3.499
3.355
7
8.
8
9.
1.383
2.262
2.821
3.250
9.
10
1.372
1.812
2.228
2.764
3.169
3.106
3.055
10
11
1.363
1.796
2.201
2.718
11
1.356
1.782
2.179
2.160
2.145
12
2.681
12
13
1.350
1.345
1.771
1.761
2.650
2.624
3.012
13
14
2.977
14
15
16
1.341
1.337
1.753
2.131
2.602
2.583
2.567
2.552
2.539
2.947
2.921
15
16
1.746
2.120
17
1.333
1.740
2.110
2.898
17
18
1.330
2.878
1.734
1.729
2.101
18
19
1.328
2.093
2.861
19
20
1.325
1.725
2.086
2.528
2.845
20
21
1.323
1.721
1.717
2.080
2.518
2.831
2.819
21
22
1.321
2.074
2.508
22
23
1.319
1.714
2.069
2.500
2.807
23
24
1.318
1.711
2.064
2.492
2.797
24
25
1.316
1.708
2.060
2.485
2.787
25
26
1.315
1.706
2.056
2.479
2.473
2.467
2.462
2.779
26
27
27
1.314
2.052
1.703
1.701
2.771
28
29
28
29
1.313
2.048
2.763
1.311
1.699
2.045
2.756
30
1.697
2.042
2.040
2.037
2.035
1.310
2.457
2.750
30
31
1.309
1.696
2.453
2.744
31
32
33
1.309
1.694
2.449
2.738
2.733
2,728
32
33
1.308
1.692
2.445
34
1.307
1.691
2.032
2.441
34
35
1.306
1.690
2.030
2.438
2.724
2.719
2.715
35
36
1.306
1.688
2.028
2.434
36
37
1.305
1.687
2.026
2.431
37
38
1.304
1.686
1.685
2.024
2.023
2.429
2.712
2.708
38
39
1.304
2.426
39
40
1.303
1.684
2.021
2.423
2.704
40
41
1.303
2.020
1.683
1.682
1.681
2.421
2.701
41
1.302
1.302
42
2.018
2.418
2.698
42
43
2.017
2.015
2.416
2.695
2.692
43
44
1.301
1.680
2.414
44
2.014
2.013
45
2.412
2.410
2.690
2.687
1.301
1.679
1.679
45
46
1.300
46
47
1.300
1.678
2.012
2.408
2.685
47
48
1.299
1.677
2.011
2.407
2.682
48
49
1.299
1.677
2.010 2.405
2.680
49
df
1o.10
taes
t0.025
t0.005
df

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step 3

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 3 steps with 3 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

$Hypothesis Tests and Confidence Intervals for Means$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.

Similar questions

Cholesterol Cholesterol in human blood is necessary, but too much can lead to health problems. There are three main types of cholesterol: HDL (high-density lipoproteins), LDL (low-density lipoproteins), and VLDL (very low-density lipoproteins). HDL is considered “good” cholesterol; LDL and VLDL are considered “bad” cholesterol. A standard fasting cholesterol blood test measures total cholesterol, HDL cholesterol, and triglycerides. These numbers are used to estimate LDL and VLDL, which are difficult to measure directly. Your doctor recommends that your combined LDL/VLDL cholesterol level be less than 130 milligrams per deciliter, your HDL cholesterol level be at least 60 milligrams per deciliter, and your total cholesterol level be no more than 200 milligrams per deciliter. (a) Write a system of linear inequalities for the recommended cholesterol levels. Let x represent the HDL cholesterol level, and let y represent the combined LDL VLDL cholesterol level. (b) Graph the system of inequalities from part (a). Label any vertices of the solution region. (c) Is the following set of cholesterol levels within the recommendations? Explain. LDL/VLDL: 120 milligrams per deciliter HDL: 90 milligrams per deciliter Total: 210 milligrams per deciliter (d) Give an example of cholesterol levels in which the LDL/VLDL cholesterol level is too high but the HDL cholesterol level is acceptable. (e) Another recommendation is that the ratio of total cholesterol to HDL cholesterol be less than 4 (that is, less than 4 to 1). Identify a point in the solution region from part (b) that meets this recommendation, and explain why it meets the recommendation.
Dr. Jones conducted a study examining the relationship between the amount of sugar in a child’s diet and the activity level of the child. A sample of 30 four-year-old children from a local preschool was used in the study. Sugar consumption was measured by interviewing the parents about each child’s diet. Based on the result of the interview, each child was then placed into one of two groups: high sugar consumption and low sugar consumption. Activity level was measured by observing the children during a regular preschool afternoon. Finally, Dr. Jones compared the activity level for the high-sugar group with the activity level for the low-sugar group. Explain why Dr. Jones’ study is not an example of the experimental research strategy and provide way that it can be tested experimentally.
Shrubs that Withstand Fire Fire is a serious threat to shrubs in dry climates. Some shrubs can resprout from their roots after their tops are destroyed. One study of resprouting took place in a dry area of Mexico. The investigators first clipped the tops of all the shrubs in the study. For the treatment, they then applied a propane torch to the stumps of the shrubs to simulate a fire, and for the control the stumps were left alone. The study included 24 shrubs of which 12 were randomly assigned to the treatment and the remaining 12 to the control. A shrub is a success if it resprouts. For the shrub Xerospirea hartwegiana, all 12 shrubs in the control group resprouted, whereas only 8 in the treatment group resprouted. How much does burning reduce the proportion of shrubs of this species that resprout? Give the 95% plus four confidence interval for the amount by which burning reduces the proportion of shrubs of this species that resprout. The plus four method is particularly helpful…
A magazine published a study on the ammonia levels near the exit ramp of a highway tunnel. The data in the table below represent daily ammonia concentrations (in parts per million) on eight randomly selected days during the afternoon drive time. Complete parts a through c.
A recent drug survey showed an increase in the use of drugs and alcohol among local high school seniors as compared to the national percent. Suppose that a survey of 100 local seniors and 100 national seniors is conducted to see if the proportion of drug and alcohol use is higher locally than nationally. Locally, 65 seniors reported using drugs or alcohol within the past month, while 60 national seniors reported using them.