HERMODYNAMICCS: Given the following hypothetical thermochemical equations: AH = -1049.3 kJ AH = -1500.6 kJ 2QJ3 (g) + 3Q2X (g) → 4Q2 (g) + 3J2X (1) 4QJ3 (g) + 3X2 (g) – 2Q2 (g) + 6J2X (1) Calculate the value of AH (in kJ) for the reaction: Q2 (g) + ½ X2 (g) - Q2X (g) (Round off final answer to ONE decimal place)

HERMODYNAMICCS: Given the following hypothetical thermochemical equations: AH = -1049.3 kJ AH = -1500.6 kJ 2QJ3 (g) + 3Q2X (g) → 4Q2 (g) + 3J2X (1) 4QJ3 (g) + 3X2 (g) – 2Q2 (g) + 6J2X (1) Calculate the value of AH (in kJ) for the reaction: Q2 (g) + ½ X2 (g) - Q2X (g) (Round off final answer to ONE decimal place)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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THERMODYNAMICS: Given the following hypothetical thermochemical equations: 2QJ3 (g) + 3Q2X (g) – 4Q2 (9) + 3J2X (1) AH = -1,017.3 kJ 4QJ3 (g) + 3X2 (g) → 202 (9) + 6J2X (1) AH = -1,548.8 kJ Calculate the value of AH (in kJ) for the reaction: Q2 (g) + % X2 (g) –→ Q2X (g) (Round off the final answer to ONE decimal place. Do not include unit.)
THERMODYNAMICS: Given the following hypothetical thermochemical equations: 2QJ3 (g) + 3Q2X (g) – 4Q2 (g) + 3J2X (1) AH = -1,096.4 kJ 4QJ3 (g) + 3X2 (g) → 202 (g) + 6J2X (1) AH = -1,548.8 kJ Calculate the value of AH (in kJ) for the reaction: Q2 (g) + % X2 (g) –→ Q2X (g) (Round off the final answer to ONE decimal place. Do not include unit,.)
THERMODYNAMICS: Calculate the value of AH (in kJ) for the reaction, 2AR3 (9) + Q (s) → A2R4 (g) + QR2 (s) given the following hypothetical thermochemical equations: 2AR3 (g) + 2AX (g) → A2R4 (9) + 2XAR (g) ΔΗ = -88.4 kJ AX (g) + ½R2 (g) → XAR (g) AH = -164.8 kJ Q (s) + R2 (g) –→ QR2 (s) AH = -520.4 kJ (Round off the final answer to ONE decimal place. Do not include the unit.)
Given the following thermochemical equations: C2H29) + 5 02(9) 2C02(g) + H201) AH° = -1229.5 kJ AH° = -393.5 kJ C(6) + 02(g) → C02(g) 1 H2(9) +5 02(9) → H20) AH° = -285.5 kJ 2 Calculate the enthalpy (in kJ) for this reaction: 206) + H2(g) → C,H2(9)
The following thermochemical equation is for the reaction of carbon dioxide(g) with hydrogen(g) to form acetylene(g) (C,H) and water(g). 2C02(g) + 5H2(g)–C,H2(g) + 4H,O(g) AH = 46.5 kJ When 15.3 grams of carbon dioxide(g) react with excess hydrogen(g), kJ of energy are | Hint: An amount of energy is expressed as a positive number. The sign of AH in the thermochemical equation indicates whether the energy is absorbed or evolved.
Rearrange the thermochemical equations given to determine the AH value for the equation of interest. Determine: 2 Fe203(s) + 3 C(s) → 3 CO2(g) + 4 Fe(s) Given Enthalpy (K/mol) 3 -833.8 O2(g) Fe203(s) 2 1. 2 Fe(s) + ch 2. C(s) + - O2(8) → CO(g) -110.4 1 O2(g) → CO2(g) -264.8 3. CO(g) + K/mol
THERMODYNAMICS: Calculate the value of AH (in kJ) for the reaction, 2AR3 (g) + Q (s)→ A2R4 (g) + QR2 (s) given the following hypothetical thermochemical equations: 2AR3 (g) + 2AX (g) → A2R4 (g) + 2XAR (g) AH = -87.2 kJ AX (g) + ½R2 (g) → XAR (g) AH = -157.3 kJ Q (s) + R2 (g) – QR2 (s) AH = -510.2 kJ (Round off the final answer to ONE decimal place. Do not include the unit.)
7.Using the following standard enthalpies of reaction4NH3(g) + 7 O2(g) 4 NO2(g) + 6 H2O(l)H ̊rxn= -1395 kJN2(g) + 2 O22 NO2(g)H ̊rxn= +67.4 kJFind the standard enthalpy of reaction for the equation:2N2(g) + 6 H2O(l) 4 NH3(g) + 3 O2(g) Based on your work above, determine the standard enthalpy of reaction for the following equation:N2(g) + 3 H2O(l) 2 NH3(g) + 3/2 O2(g)
The following thermochemical equation is for the reaction of Fe,0, (s) with hydrogen (g) to form iron(s) and water (g). Fe₂O₂ (s) + 4H₂(g) 3Fe(s) + 4H₂O(g) AH = 151 kJ Use the References to access important values if needed for this question. When 86.8 grams of Fe₂O4(s) react with excess hydrogen(g). Hint: An amount of energy is expressed as a positive number. The sign of AH in the thermochemical equation indicates whether the energy is absorbed or evolved. Submit Answer kJ of energy are
A food product containing 82% moisture content is being frozen. Predict the specific heat of the product at -8 ° C when 82% of the air is frozen. The specific heat of the dry product is 2.5 kJ / (kg ° C). It is assumed that the specific heat of water at -10 ° C is the same as that of water at 0 ° C, and that the specific heat of ice follows the function Cp ice = 0.0062 T frozen + 2.0649. Cp of frozen product = answer J / kg ° C.
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THERMODYNAMICS Given the following hypothetical thermochemical equations: 2QJ3 (g) + 302X (g) 402 (9) + 3J2X (I) AH = -1,034 kJ 4QJ3 (g) + 3X2 (g) 202 (g) + 6J2X () AH = -1,577.7 kJ Calculate the value of AH (in kJ) for the reaction 02 (g) % X2 (g) Q2X (g) (Round off the final answer to ONE decimal place. Do not include unit)