Given the following hypothetical thermochemical equations: A2D (g) + 3/2 E2 (g) → A2E (1) + DE2 (g) AH = -568.7 kJ MD2 (1) + 3 E2 (g) → ME2 (g) + 2DE2 (g) AH-1042.7 kJ Calculate the value of AH (in kJ) for the reaction: MD2 (1) + 2A2E (1)→ ME2 (g) + 2A2D (g) Final answer: ONE decimal place.

Given the following hypothetical thermochemical equations: A2D (g) + 3/2 E2 (g) → A2E (1) + DE2 (g) AH = -568.7 kJ MD2 (1) + 3 E2 (g) → ME2 (g) + 2DE2 (g) AH-1042.7 kJ Calculate the value of AH (in kJ) for the reaction: MD2 (1) + 2A2E (1)→ ME2 (g) + 2A2D (g) Final answer: ONE decimal place.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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4. Hess's Law Calculate AH for the reaction: 2 C(s) + H2(g) → C:H2(g), given the following chemical equations and their respective enthalpy changes: C2H2(g)+02(g)→2CO2(g)+H20(1) AH, = -1299.6 kJ (1) %3D C(s)+02(g)→CO2(g) AH, = -393.5 kJ (2) H2(g)+502(g)→H20(1) AH3 = -285.8 kJ (3)
Write a balanced thermochemical expression depicting the formation of 1 mol of the compound below from it's elements. Note: ΔH∘fΔHf∘ for C6H12O6 (s) = -1274.4 kJ/mol 6 CO2 (g) + 6 H2O (l) ⟶⟶ C6H12O6 (s) + 6 O2 (g) ΔH∘ΔH∘ = -1274.4 kJ
Determine the enthalpy of the reaction: 3Fe,O; (s) + CO (g) → CO, (g) + 2Fe;O4 (s), given the following reactions. 38. Fe,O3 (s) + 3CO (g) → 2Fe (s) + 3CO, (g) AH= -28.0 kJ 3Fe (s) + 4CO2 (s) → 4CO (g) + Fe;O4 (s) AH =+12.5 kJ A) 40.5 +109 -59.0 -109
2. Consider the following thermochemical equations: C(graphite) + O2 (g) → co2 (g) AH°rn = -393.5 kJ H2 (g) + % 02 (g) → H;0 (/) AHO = -285.8 kJ 2 C:Hs (g) + 702 (g) → 4 CO2 (g) + 6 H20 (1) AH°rn = -3119.6 kJ a. Derive the thermochemical equation describing the combustion of two moles of C(graphite). b. Derive the thermochemical equation describing the combustion of three moles of H2 (g). c. Derive the thermochemical equation describing the synthesis of one mole of C,Hg (9) from carbon dioxide and water. d. Use Hess's Law and the three thermochemical equations you derived in parts a-c to determine the AH°ran for the following reaction: 2C (graphite) + 3 H2 (g) → C;Hs (g)
Given: 4AICI3(s) + 302(g) → 2Al,O3(s) + 6C12(g); AH=-529.0 kJ determine AH for the following thermochemical equation. Cl,(3) + Al,O;(s) → AICI,(9) + 02(g) O +88.2 kJ O +264.5 kJ O +176.3 kJ O -176.3 kJ O +529.0 kJ
A chemist measures the enthalpy change AH during the following reaction: Fe(s) + 2 HCl(g) →FeCl₂(s) + H₂(g) Use this information to complete the table below. Round each of your answers to the nearest kJ/mol. reaction AH=157. kJ FeCl₂ (s) + H₂(g) → Fe(s) + 2HC1 (g) 2Fe (s) + 4H C1 (g) 3 FeCl₂ (s) + 3H₂(g) 2FeCl₂ (s) + 2H₂(g) 3Fe (s) + 6HCl (g) ΔΗ [ kJ kJ kJ 0x x10 × Ś
Given the following thermochemical equations: C2H29) + 5 02(9) 2C02(g) + H201) AH° = -1229.5 kJ AH° = -393.5 kJ C(6) + 02(g) → C02(g) 1 H2(9) +5 02(9) → H20) AH° = -285.5 kJ 2 Calculate the enthalpy (in kJ) for this reaction: 206) + H2(g) → C,H2(9)
7. Find AH for the following reaction: C6H12O6 (s) → 2 C₂H5OH (l) + 2 CO₂ (g) The standard enthalpies of formation are: 6 C (s) + 6 H₂(g) + 3 O₂(g) → C6H12O6 (s) 2 C(s) + 3 H₂(g) + O2(g) → C₂H5OH (l) C(s) + O₂(g) → CO₂ (g) AH-1273 kJ/mol AH=-278 kJ/mol AH=-394 kJ/mol
Given the following thermochemical equations: 4 FeS2(s) + 11 O2(g) 2 H2S(g) + 3 O2(g) → 2 Fe2O3(s) + 8SO2(g) → 2 H₂O(1) +2 SO2(g) →2 Fe2O3(s) 4 FeO(s) + O2(g) →2 FeO(s) 2 Fe(s) + O2(g) H2(g) +S(s) 2 H2(g) + O2(g) → H₂S(g) → 2 H₂O(1) Compute the AH for FeS2(s) in kJ/mol. A)-1233.9 kJ/mol B) -2893.9 kJ/mol C) -24.3 kJ/mol D) -183.5 kJ/mol E) -70.0 kJ/mol O A OB Oc OD OE (kJ/mol) ΔH° = -3307.9 - 1125.2 -578.2 -544 - 20.2 -571.7
Using the provided table and the equation below, determine the heat of formation (in kJ/mol) for PbS. 2 PbS (s) + 3 O₂ (g) → 2 SO₂ (g) + 2 PbO (s) AH° = -828.4 kJ/mol Substance O₂ (g) SO: (g) PbO (S) AHf (kJ/mol) 0 -296.9 -217.3
Consider the following information: A + B → C + D AH° = -15 kJ mol-1 C + D → E AH° = +5 kJ mol-1 Calculate the enthalpy for the following reaction: 2A+2B → 2E