2. Consider the following thermochemical equations: C(graphite) + 0, (g) → co; (g) AH = -393.5 kJ H2 (g) + % O; (g) → H,O (/) AH = -285.8 kJ 2 C:HG (g) + 7 02 (g) → 4 CO2 (g) + 6 H20 (1) AH°n = -3119.6 kJ a. Derive the thermochemical equation describing the combustion of two moles of C(graphite). b. Derive the thermochemical equation describing the combustion of three moles of H2 (g).

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### Thermochemical Equations Task

#### Consider the following thermochemical equations:

1. **\[ \text{C(graphite)} + \text{O}_2 \, (g) \rightarrow \text{CO}_2 \, (g) \]**
   - \(\Delta H^\circ_{\text{rxn}} = -393.5 \, \text{kJ}\)

2. **\[ \text{H}_2 \, (g) + \frac{1}{2} \text{O}_2 \, (g) \rightarrow \text{H}_2\text{O} \, (l) \]**
   - \(\Delta H^\circ_{\text{rxn}} = -285.8 \, \text{kJ}\)

3. **\[ 2 \text{C}_2\text{H}_6 \, (g) + 7 \text{O}_2 \, (g) \rightarrow 4 \text{CO}_2 \, (g) + 6 \text{H}_2\text{O} \, (l) \]**
   - \(\Delta H^\circ_{\text{rxn}} = -3119.6 \, \text{kJ}\)

#### Tasks:

**a. Derive the thermochemical equation describing the combustion of two moles of C(graphite).**

**b. Derive the thermochemical equation describing the combustion of three moles of H\(_2 \) (g).**

**c. Derive the thermochemical equation describing the synthesis of one mole of C\(_2\)H\(_6(g)\) from carbon dioxide and water.**

**d. Use Hess’s Law and the three thermochemical equations you derived in parts a-c to determine the \(\Delta H^\circ_{\text{rxn}}\) for the following reaction:**

\[ 2 \text{C (graphite)} + 3 \text{H}_2 \, (g) \rightarrow \text{C}_2\text{H}_6 \, (g) \]

### Explanation

This exercise involves manipulating and combining standard thermochemical equations to calculate the enthalpy change for a complex reaction using Hess’s Law. Each part requires deriving or rearranging equations to fit the specified conditions and calculating using given \(\Delta H^\circ_{\text{rxn}}\) values
Transcribed Image Text:### Thermochemical Equations Task #### Consider the following thermochemical equations: 1. **\[ \text{C(graphite)} + \text{O}_2 \, (g) \rightarrow \text{CO}_2 \, (g) \]** - \(\Delta H^\circ_{\text{rxn}} = -393.5 \, \text{kJ}\) 2. **\[ \text{H}_2 \, (g) + \frac{1}{2} \text{O}_2 \, (g) \rightarrow \text{H}_2\text{O} \, (l) \]** - \(\Delta H^\circ_{\text{rxn}} = -285.8 \, \text{kJ}\) 3. **\[ 2 \text{C}_2\text{H}_6 \, (g) + 7 \text{O}_2 \, (g) \rightarrow 4 \text{CO}_2 \, (g) + 6 \text{H}_2\text{O} \, (l) \]** - \(\Delta H^\circ_{\text{rxn}} = -3119.6 \, \text{kJ}\) #### Tasks: **a. Derive the thermochemical equation describing the combustion of two moles of C(graphite).** **b. Derive the thermochemical equation describing the combustion of three moles of H\(_2 \) (g).** **c. Derive the thermochemical equation describing the synthesis of one mole of C\(_2\)H\(_6(g)\) from carbon dioxide and water.** **d. Use Hess’s Law and the three thermochemical equations you derived in parts a-c to determine the \(\Delta H^\circ_{\text{rxn}}\) for the following reaction:** \[ 2 \text{C (graphite)} + 3 \text{H}_2 \, (g) \rightarrow \text{C}_2\text{H}_6 \, (g) \] ### Explanation This exercise involves manipulating and combining standard thermochemical equations to calculate the enthalpy change for a complex reaction using Hess’s Law. Each part requires deriving or rearranging equations to fit the specified conditions and calculating using given \(\Delta H^\circ_{\text{rxn}}\) values
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