(1)Calculate AH for the reaction:2 CO2) + 3H2O→ C2H6O+3028)Given the following chemical equations and their respective enthalpy changes:2 C2H6O) + O2g) →2 C2H4O) +2 H2O AH=-508.7 kJC2H4O0 + 2%0268) →2 CO2) + 2 H2O AH=-1,458.7 kJ%3D(2)Calculate AH for the reaction:H(g) + Brg) → HBr(g)CHECPGiven the following chemical equations and their respective enthalpy changes:H2(8) →2 H(g)Br2g) →2 Brg)H2(3) + Br2g) → 2 HBrg)AH = +436.4 k.AH = +192.5 kJ3032AH =-72.4 kJ Given the thermochemical data:2 NaCle) + H2O0 → 2 HClg) + Na2O(s)NOg) + NO2@) +Na2O(s) →2 NaNO2(5)NOg) + NO2g) → N2O(g) + O2(g)2 HNO20 → N2O(g) + Oz(g) + H2O(oAH = +507 kJ(5)AH =-427 kJAH =-43 kJAH = +34 kJ%3DDetermine the enthalpy of the reaction:HClg) + NaNO2(s) → HNO21) + NaCl6)(6)Determine the enthalpy of the following reaction below:Zns) + S(9) + 202(g) → ZNSO4(5)Given the thermochemical data:Zng) + S(s) → ZnS(s)2 ZnS(9) + 302(g)→2 ZnO(s) + 2 SO2(8)2 SO2g) +O2(g) → 2 SO3(g)ZnO(s) + SO3(g) → ZNSO46)AH =-183.92 kJAH =-927.54 kJAH =-196.04 kJAH =-230.32 kJ

Answered: Image /qna-images/answer/7f5da0be-ae5e-40da-b4b2-f3ad5f5f4b51.jpg

(1) Calculate AH for the reaction: 2 CO2) + 3H2O C2H6O+302g) Given the following chemical equations and their respective enthalpy changes: 2 C2H6O + O28) 2 C2H4O +2 H2O AH=-508.7 kJ C2H4O+ 2%026®) →2 CO2() + 2 H2O AH=-1,458.7 kJ %3D

(1) Calculate AH for the reaction: 2 CO2) + 3H2O C2H6O+302g) Given the following chemical equations and their respective enthalpy changes: 2 C2H6O + O28) 2 C2H4O +2 H2O AH=-508.7 kJ C2H4O+ 2%026®) →2 CO2() + 2 H2O AH=-1,458.7 kJ %3D

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Thermochemistry

Thermochemistry can be considered as a branch of thermodynamics that deals with the connections between warmth, work, and various types of energy, formed because of different synthetic and actual cycles. Thermochemistry describes the energy changes that occur as a result of reactions or chemical changes in a substance.

Exergonic Reaction

The term exergonic is derived from the Greek word in which ‘ergon’ means work and exergonic means ‘work outside’. Exergonic reactions releases work energy. Exergonic reactions are different from exothermic reactions, the one that releases only heat energy during the course of the reaction. So, exothermic reaction is one type of exergonic reaction. Exergonic reaction releases work energy in different forms like heat, light or sound. For example, a glow stick releases light making that an exergonic reaction and not an exothermic reaction since no heat is released. Even endothermic reactions at very high temperature are exergonic.

Question

(1)
Calculate AH for the reaction:
2 CO2) + 3H2O→ C2H6O+3028)
Given the following chemical equations and their respective enthalpy changes:
2 C2H6O) + O2g) →2 C2H4O) +2 H2O AH=-508.7 kJ
C2H4O0 + 2%0268) →2 CO2) + 2 H2O AH=-1,458.7 kJ
%3D
(2)
Calculate AH for the reaction:
H(g) + Brg) → HBr(g)
CHECP
Given the following chemical equations and their respective enthalpy changes:
H2(8) →2 H(g)
Br2g) →2 Brg)
H2(3) + Br2g) → 2 HBrg)
AH = +436.4 k.
AH = +192.5 kJ
3032
AH =-72.4 kJ

Given the thermochemical data:
2 NaCle) + H2O0 → 2 HClg) + Na2O(s)
NOg) + NO2@) +Na2O(s) →2 NaNO2(5)
NOg) + NO2g) → N2O(g) + O2(g)
2 HNO20 → N2O(g) + Oz(g) + H2O(o
AH = +507 kJ
(5)
AH =-427 kJ
AH =-43 kJ
AH = +34 kJ
%3D
Determine the enthalpy of the reaction:
HClg) + NaNO2(s) → HNO21) + NaCl6)
(6)
Determine the enthalpy of the following reaction below:
Zns) + S(9) + 202(g) → ZNSO4(5)
Given the thermochemical data:
Zng) + S(s) → ZnS(s)
2 ZnS(9) + 302(g)→2 ZnO(s) + 2 SO2(8)
2 SO2g) +O2(g) → 2 SO3(g)
ZnO(s) + SO3(g) → ZNSO46)
AH =-183.92 kJ
AH =-927.54 kJ
AH =-196.04 kJ
AH =-230.32 kJ

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