THERMODYNAMICS: Given the following hypothetical thermochemical equations: 2QJ3 (g) + 3Q2X (g) → 4Q2 (g) + 3J2X (1) AH = -1,096.4 kJ 4QJ3 (g) + 3X2 (9) –→ 202 (g) + 6J2X (1) AH = -1,548.8 kJ Calculate the value of AH (in kJ) for the reaction: Q2 (g) + ½ X2 (g) → Q2X (g) (Round off the final answer to ONE decimal place. Do not include unit.)
THERMODYNAMICS: Given the following hypothetical thermochemical equations: 2QJ3 (g) + 3Q2X (g) → 4Q2 (g) + 3J2X (1) AH = -1,096.4 kJ 4QJ3 (g) + 3X2 (9) –→ 202 (g) + 6J2X (1) AH = -1,548.8 kJ Calculate the value of AH (in kJ) for the reaction: Q2 (g) + ½ X2 (g) → Q2X (g) (Round off the final answer to ONE decimal place. Do not include unit.)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![THERMODYNAMICS: Given the following hypothetical thermochemical equations:
2QJ3 (g) + 3Q2X (g) – 4Q2 (g) + 3J2X (1)
AH = -1,096.4 kJ
4QJ3 (g) + 3X2 (g) → 202 (g) + 6J2X (1)
AH = -1,548.8 kJ
Calculate the value of AH (in kJ) for the reaction:
Q2 (g) + % X2 (g) –→ Q2X (g)
(Round off the final answer to ONE decimal place. Do not include unit,.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff076d2ea-7ac8-40fa-a41c-eeac1f170a9d%2Fdf0215bd-2af0-4a99-922a-15b6ec26ba16%2Fkl698ze_processed.png&w=3840&q=75)
Transcribed Image Text:THERMODYNAMICS: Given the following hypothetical thermochemical equations:
2QJ3 (g) + 3Q2X (g) – 4Q2 (g) + 3J2X (1)
AH = -1,096.4 kJ
4QJ3 (g) + 3X2 (g) → 202 (g) + 6J2X (1)
AH = -1,548.8 kJ
Calculate the value of AH (in kJ) for the reaction:
Q2 (g) + % X2 (g) –→ Q2X (g)
(Round off the final answer to ONE decimal place. Do not include unit,.)
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