THERMODYNAMICS Given the following hypothetical thermochemical equations: 2QJ3 (g) + 3Q2X (g) 402 (g) + 3J2X () AH = -1,034 kJ 4QJ3 (g) + 3X2 (g) 202 (g) + 6J2X () AH = -1.577.7 kJ Calculate the value of AH (in kJ) for the reaction: 02 (g) % X2 (g) – Q2X (g) (Round off the final answer to ONE decimal place. Do not include unit)

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THERMODYNAMICS Given the following hypothetical thermochemical equations:
2QJ3 (g) + 302X (g) 402 (9) + 3J2X (I)
AH = -1,034 kJ
4QJ3 (g) + 3X2 (g) 202 (g) + 6J2X ()
AH = -1,577.7 kJ
Calculate the value of AH (in kJ) for the reaction
02 (g) % X2 (g) Q2X (g)
(Round off the final answer to ONE decimal place. Do not include unit)
Transcribed Image Text:THERMODYNAMICS Given the following hypothetical thermochemical equations: 2QJ3 (g) + 302X (g) 402 (9) + 3J2X (I) AH = -1,034 kJ 4QJ3 (g) + 3X2 (g) 202 (g) + 6J2X () AH = -1,577.7 kJ Calculate the value of AH (in kJ) for the reaction 02 (g) % X2 (g) Q2X (g) (Round off the final answer to ONE decimal place. Do not include unit)
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