Half-life equation for first-order reactions: 0.693 11/2k The integrated rate law allows chemists to predict the reactant concentration after a certain amount of time, or the time it would take for a certain concentration to be reached. The integrated rate law for a first-order reaction is: where t₁/2 is the half-life in seconds (s), and k is the rate constant in inverse seconds (s1). [A] = [A]oe -kt Part A Now say we are particularly interested in the time it would take for the concentration to become one-half of its initial value. Then we could [A]。 substitute for [A] and rearrange the equation to: 0.693 t1/2= This equation calculates the time required for the reactant concentration to drop to half its initial value. In other words, it calculates the half-life. To calculate the half-life, plug the value for k into the half-life equation and solve. What is the half-life of a first-order reaction with a rate constant of 9.00x10-4 s¹? Express your answer with the appropriate units. ? Value Units Submit Request Answer ▾ Part B What is the rate constant of a first-order reaction that takes 592 seconds for the reactant concentration to drop to half of its initial value? Express your answer with the appropriate units. View Available Hint(s) Value Submit Part C 374 Units A certain first-order reaction has a rate constant of 4.10x103 s 1. How long will it take for the reactant concentration to drop to Express your answer with the appropriate units. View Available Hint(s) of its initial value?
Half-life equation for first-order reactions: 0.693 11/2k The integrated rate law allows chemists to predict the reactant concentration after a certain amount of time, or the time it would take for a certain concentration to be reached. The integrated rate law for a first-order reaction is: where t₁/2 is the half-life in seconds (s), and k is the rate constant in inverse seconds (s1). [A] = [A]oe -kt Part A Now say we are particularly interested in the time it would take for the concentration to become one-half of its initial value. Then we could [A]。 substitute for [A] and rearrange the equation to: 0.693 t1/2= This equation calculates the time required for the reactant concentration to drop to half its initial value. In other words, it calculates the half-life. To calculate the half-life, plug the value for k into the half-life equation and solve. What is the half-life of a first-order reaction with a rate constant of 9.00x10-4 s¹? Express your answer with the appropriate units. ? Value Units Submit Request Answer ▾ Part B What is the rate constant of a first-order reaction that takes 592 seconds for the reactant concentration to drop to half of its initial value? Express your answer with the appropriate units. View Available Hint(s) Value Submit Part C 374 Units A certain first-order reaction has a rate constant of 4.10x103 s 1. How long will it take for the reactant concentration to drop to Express your answer with the appropriate units. View Available Hint(s) of its initial value?
Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter12: Kinetics
Section: Chapter Questions
Problem 65E: The hydrolysis of the sugar sucrose to the sugars glucose and fructose, C12H22O11+H2OC6H12O6+C6H12O6...
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