>>>teams ["team1", "team2", "team3", "team4"] >>> rankings = [3, 2, 4, 1] >>> eliminate(teams, rankings, 1) ('team1', 'team2', 'team4')
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I'm still lost on how it works. From what I understand the code should do team 1 = 3rd place, team 2 = 2nd place, team 3 = 4th place, team 4 = 1st place. Then you filter out team 4 because you don't want anyone who ranked in that position. The output would then be: ('team1', 'team2', 'team3') but the test wants ('team1', 'team2', 'team4')?
![>>>teams ["team1", "team2", "team3", "team4"]
>>> rankings = [3, 2, 4, 1]
>>> eliminate(teams, rankings, 1)
('team1', 'team2', 'team4')](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F51f38822-a398-4e95-8c77-7b255b56c192%2F7a77379c-ca1c-405b-b232-8bb25301cce1%2Fngv7nh_processed.png&w=3840&q=75)
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- Why should you utilise the new operator when creating structure instances?Count consecutive summers def count_consecutive_summers(n): Like a majestic wild horse waiting for someone to come and tame it, positive integers can be broken down as sums of consecutive positive integers in various ways. For example, the integer 42 often used as placeholder in this kind of discussions can be broken down into such a sum in four different ways: (a) 3 + 4 + 5 + 6 + 7 + 8 + 9, (b) 9 + 10 + 11 + 12, (c) 13 + 14 + 15 and (d) 42. As the last solution (d) shows, any positive integer can always be trivially expressed as a singleton sum that consists of that integer alone. Given a positive integer n, determine how many different ways it can be expressed as a sum of consecutive positive integers, and return that count. The count of how many different ways a positive integer n can be represented as a sum of consecutive integers is also called its politeness, and can be alternatively computed by counting how many odd divisors that number has. However, note that the linked…JSON Response example when code = BAHRAIN as follows: { "Country": "Bahrain", "Tenps"il ("day": "SUNDAY", "temp"i {"day": "HONDAY", "temp": 35), ("day": "TUESDAYr, "teng": 39), ("day": "WEDNESDAY", "tenp": 37),. ("day"i "THURSDAY", "tenp": 35), ("day"i "FRIDAV", "temp": 34), ("day": "SATURDAY", "teng": 37) 1. Implement find Templ ) function as follows: Sample Eample This function will be called whenever the user change the value of the pull-down menu. This function should contact Ve the Web Service API, sending the selected country code, to Co display the information (country, daily temperatures in the week and average weekly temperature) inside the div tag whose id -result as shown in the example on the right. Country ahraln In addition, the country name and the average temperatures should be saved as one JS object inside an array in a local storage. Whenever new request is made, the countrylaverage will be saved and added to the array inside the local storage (duplicates is allowed).…
- function carLambda = [rank, &price] ()->int { cout name); model Car:: carModel; auto testLambdaPtr = testLambda (); cout << testLambdaPtr () << endl; return 0; I a. In which memory area is this element stored? Please state your choice and explain why? b. The lifetime, beginning & end, of this element? Why?#include #include #include "Product.h" using namespace std; int main() { vector productList; Product currProduct; int currPrice; string currName; unsigned int i; Product resultProduct; cin>> currPrice; while (currPrice > 0) { } cin>> currPrice; main.cpp cin>> currName; currProduct.SetPriceAndName (currPrice, currName); productList.push_back(currProduct); resultProduct = productList.at (0); for (i = 0; i < productList.size(); ++i) { Type the program's output Product.h 1 CSE Scanned Product.cpp if (productList.at (i).GetPrice () < resultProduct.GetPrice ()) { resultProduct = productList.at(i); } AM cout << "$" << resultProduct.GetPrice() << " " << resultProduct. GetName() << endl; return 0; Input 10 Cheese 6 Foil 7 Socks -1 Output#ifndef lab5ExF_h #define lab5ExF_h typedef struct point { char label[10]; double x ; // x coordinate for point in a Cartesian coordinate system double y; // y coordinate for point in a Cartesian coordinate system double z; // z coordinate for point in a Cartesian coordinate system }Point; void reverse (Point *a, int n); /* REQUIRES: Elements a[0] ... a[n-2], a[n-1] exists. * PROMISES: places the existing Point objects in array a, in reverse order. * The new a[0] value is the old a[n-1] value, the new a[1] is the * old a[n-2], etc. */ int search(const Point* struct_array, const char* target, int n); /* REQUIRES: Elements struct-array[0] ... struct_array[n-2], struct_array[n-1] * exists. target points to string to be searched for. * PROMISES: returns the index of the element in the array that contains an * instance of point with a matching label. Otherwise, if there is * no point in the array that its label matches the target-label, * it should return -1. * If there are more than…
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