Glycopeptide X is composed of a glycan Y and an octapeptide. The octapeptide was cleaved by trypsin, giving 2 tetrapeptides of exactly the same composition except for its N-terminals. When the octapeptide was cleaved by chymotrypsin, it gave a pentapeptide and a tripeptide. DNFB treatment gave DNP-ser. The composition of the octapeptide is lys, ser, trp.and leu. The leu:ser ratio is 4:1. 1. What is the sequence of this octapeptide?
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- A decapeptide which could resist burns was isolated from an endemic plant from Mt. Mayon. Deduce the amino acid sequence of the decapeptide given the following informations. Mercaptoethanol gave two pentapeptides F1 and F2. Chymotrypsin treatment of F1 releases S and a tetrapeptide (C,K,F,M) while F2 gave a dipeptide (M,S) and a tripeptide (C,F,K) F1 when treated with CNBr released a free homoserine lactone and a tetrapeptide. Trypsin treatment of F1 gave a tripeptide and a dipeptide. F2 treated with carboxypeptidase released free M while with trypsin gave free K and a tetrapeptide.The alkaline hydrolysis of pAUGCAGC oligonucleotide produces: O A. Uridine 2'-monophosphate, uridine 3'-monophosphate, cytosine 2'-monophosphate O B. Adenosine 2'-monophosphate, adenosine 3'-monophosphate, adenosine 21,5'-bisphosphate OC. Guanosine 2'-monophosphate, guanosine 3'-monophosphate, cytosine 3'-monophosphate O D. Cytidine 3'-monophosphate, guanosine 2'-monophosphate, adenine 2'-monophosphate O E. Adenine 3,5'-bisphosphate, guanine 2,5'-bisphosphate, uridine 2'-monophosphate O F. Uridine 2'-monophosphate, uridine 3'-monophosphate, guanine 3'-monophosphateA nonapeptide was treated with dithiothreitol to reduce any disulfide bridges, then partially hydrolyzed, giving rise to the following fragments. What was the sequence of the original polypeptide? Phe-Gln-Asn Pro-Arg-Gly-NH2 Cys-Tyr-Phe Asn-Cys-Pro-Arg Tyr-Phe-Gln-Asn O Cys-Tyr-Phe-GIn-Asn-Cys-Pro-Arg-Gly-NH2 O H2N-Gly-Arg-Pro-Cys-Asn-Gln-Phe-Tyr-Cys O Gly-Arg-Pro-Cys-Tyr-Phe-Gln-Asn-Cys-NH2 Cys-Pro-Arg-Gly-NH2-Cys-Tyr-Phe-Gln-Asn O None of these are correct.
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- A peptide with endorphin-like property was produced and obtained from the blood. This was sequence using the protocol: Treatment with streptococcal protease gave a tripeptide and a tetrapeptide. Treatment with trypsin gave two tripeptides and an amino acid. Treatment of the 2 tripeptide products in 1.2 with 2,4-dinitrophenol gave DNP- S, and DNP-E and a mixture of amino acids. The composition of the peptide is G, E, S, and K in a 2:1:1:3 molar ratio. What is the sequence of the peptide?A pentapeptide was found to have the composition Ala Arg Gly Pro Trp. Reaction of the pentapeptide with Sanger’s reagent, followed by hydrolysis, gave the DNP derivative of proline. Treatment of the pentapeptide with carboxypeptidase initially produced alanine. Treatment of the pentapeptide with trypsin gave a tetrapeptide which, when treated with chymotrypsin, produced a tripeptide. What is the sequence of the pentapeptide? (note: trypsin cleaves after basic amino acids) *A) Draw L-histidine. Label all ionizable groups with the appropriate pKa.