Glutamine carries r 4ortra mi っtis
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
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Question
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![Which of the following statements are TRUE?
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Glutamine carries nitrogen from most tissues to the liver for disposal
a
after transamination reactions.
Ammonia is removed from muscle tissue by the glucose-alanine cycle
which converts pyruvate to alanine using glutamate as the nitrogen
b
donor.
Ammonia is removed from liver tissue by the production of urea in the
urea cycle using glutamate and glutamine as sole nitrogen donors.
The equilibrium constant for the phosphorylation of glucose to
glucose-6-phosphate (AG° =(+13.8 kJ/mol) is 0.0038.
If glucose were phosphorylated according to Statement D the
equilibrium concentration of glucose-6-phosphate under cellular
conditions (both glucose and phosphate are 5 mM) is 0.000000095.
One way to increase the amount of glucose-6-phosphate (Statement D)
is to increase the concentrations of reactants thus decreasing the mass
action ratio (AG = AGO + RTIN [products]/[reactants]) making the
f.
reaction as written more feasible. The concentration of glucose
required to achieve a glucose-6-phosphate concentration of 250 µM is](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd5cc39c9-8b2b-4beb-a3cb-5d1bdcb587ab%2Fe29643ca-3eaa-48a2-b617-52cbec97901c%2Fuc0xng7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Which of the following statements are TRUE?
Multiple answers: Multiple answers are accepted for this question
Select one or more answers and submit. For keyboard navigation... SHOW MORE V
Glutamine carries nitrogen from most tissues to the liver for disposal
a
after transamination reactions.
Ammonia is removed from muscle tissue by the glucose-alanine cycle
which converts pyruvate to alanine using glutamate as the nitrogen
b
donor.
Ammonia is removed from liver tissue by the production of urea in the
urea cycle using glutamate and glutamine as sole nitrogen donors.
The equilibrium constant for the phosphorylation of glucose to
glucose-6-phosphate (AG° =(+13.8 kJ/mol) is 0.0038.
If glucose were phosphorylated according to Statement D the
equilibrium concentration of glucose-6-phosphate under cellular
conditions (both glucose and phosphate are 5 mM) is 0.000000095.
One way to increase the amount of glucose-6-phosphate (Statement D)
is to increase the concentrations of reactants thus decreasing the mass
action ratio (AG = AGO + RTIN [products]/[reactants]) making the
f.
reaction as written more feasible. The concentration of glucose
required to achieve a glucose-6-phosphate concentration of 250 µM is
![Please save all answers. Questions that you save can still b
ave 1 UNSAVED ANSWER -
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i Multiple answers: Multiple answers are accepted for this question
Select one or more answers and submit. For keyboard navigation... SHOW MORE V
Glutamine carries nitrogen from most tissues to the liver for disposal
a
after transamination reactions.
Ammonia is removed from muscle tissue by the glucose-alanine cycle
which converts pyruvate to alanine using glutamate as the nitrmgen
b
donor.
Ammonia is removed from liver tissue by the production of urea in the
urea cycle using glutamate and glutamine as sole nitrogen donors.
The equilibrium constant for the phosphorylation of glucose to
d.
glucose-6-phosphate (AG =(+13.8 kJ/mol) is 0.0038.
If glucose were phosphorylated according to Statement D the
equilibrium concentration of glucose-6-phosphate under cellular
conditions (both glucose and phosphate are 5 mM) is 0.000000095.
e
One way to increase the amount of glucose-6-phosphate (Statement D)
is to increase the concentrations of reactants thus decreasing the mass
action ratio (AG = AGO + RTIN [products]/[reactants]) making the
f
reaction as written more feasible. The concentration of glucose
required to achieve a glucose-6-phosphate concentration of 250 µM is
13м.
IUnancworod](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd5cc39c9-8b2b-4beb-a3cb-5d1bdcb587ab%2Fe29643ca-3eaa-48a2-b617-52cbec97901c%2Fdoesvt_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Please save all answers. Questions that you save can still b
ave 1 UNSAVED ANSWER -
SAVE ALL ANSWERS
i Multiple answers: Multiple answers are accepted for this question
Select one or more answers and submit. For keyboard navigation... SHOW MORE V
Glutamine carries nitrogen from most tissues to the liver for disposal
a
after transamination reactions.
Ammonia is removed from muscle tissue by the glucose-alanine cycle
which converts pyruvate to alanine using glutamate as the nitrmgen
b
donor.
Ammonia is removed from liver tissue by the production of urea in the
urea cycle using glutamate and glutamine as sole nitrogen donors.
The equilibrium constant for the phosphorylation of glucose to
d.
glucose-6-phosphate (AG =(+13.8 kJ/mol) is 0.0038.
If glucose were phosphorylated according to Statement D the
equilibrium concentration of glucose-6-phosphate under cellular
conditions (both glucose and phosphate are 5 mM) is 0.000000095.
e
One way to increase the amount of glucose-6-phosphate (Statement D)
is to increase the concentrations of reactants thus decreasing the mass
action ratio (AG = AGO + RTIN [products]/[reactants]) making the
f
reaction as written more feasible. The concentration of glucose
required to achieve a glucose-6-phosphate concentration of 250 µM is
13м.
IUnancworod
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