Given your understanding of what initiates and controls failure in materials, which of the following will increase the failure strength or lifetime of a test piece or component and why? 0 a. Decreasing the difference between the maximum and minimum stress values, as this effects the stress concentration factor b. Decreasing the temperature below the brittle-ductile transition temperature, to make it harder c. Polishing to reduce surface defects Od. Increasing its volume, to give a larger cross sectional area Oe. Increasing the grain size so there are less grain boundaries to initiate failure

Given your understanding of what initiates and controls failure in materials, which of the following will increase the failure strength or lifetime of a test piece or component and why? 0 a. Decreasing the difference between the maximum and minimum stress values, as this effects the stress concentration factor b. Decreasing the temperature below the brittle-ductile transition temperature, to make it harder c. Polishing to reduce surface defects Od. Increasing its volume, to give a larger cross sectional area Oe. Increasing the grain size so there are less grain boundaries to initiate failure

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: Example: the low cycle fatigue of a certain steel is given by life cycle equation-2: (of/E)=0.005…

A: The fatigue strength of steel /Modulus of elasticity(E), The fatigue Ductility coefficient is, The…

Q: A bar of a steel alloy that exhibits the stress-strain behavior shown in the Animated Figure 6.22 is…

Q: At a temperature of 60°F, a 0.04-in. gap exists between the ends of the two bars shown. Bar (1) is…

A: Initial temperature (Ti) = 60°F Bar-1: Width of bar1 = 3 in. Thickness of bar1 = 0.75 in. L1 = 32…

Q: For a specimen of a steel alloy with a plane strain fracture toughness of 80 MPa√m, fracture results…

A: Given KIC=80MPamσ=510MPaa=6mm Consider the formula KIC=Yσπa80=Y×5103.14×6Y=0.036

Q: Fc FA Fa Fc

A: According to given data Fa , Fb , Fc principal stresses are shown in three elements We need to…

Q: Sketch the stress–strain behavior of steel, and identify different levels of strength. What is a…

A: It is required to draw the stress strain curve for steel.

Q: A bronze rod is rigidly attached between an aluminum rod and a steel rod as shown in the figure…

Q: The following figure shows the tensile stress-strain curve for a plain-carbon steel. 600 80 500 MPa…

A: a) Ultimate tensile strength is 580 MPa (Approximately).

Q: A tensile force of 5 kN produce an elastic reduction in diameter of 4 x 10-4 mm on a metal alloy…

A: given data: Force (F)=5 KNdiameter (d)=6 mmreduction in diameter(∆d)=4×10-4 mm

Q: 1.14 The stress-strain relation shown in Figure P1.14 was obtained during the ten- sile test of an…

A: The given stress-strain relationship of aluminum alloy

Q: An aluminum alloy bar with a radius of 7 mm was subjected to tension until fracture and produced…

A: Since we answer Three subpart at a time so we will answer the first three. Please resubmit another…

Q: In a tensile test a metal begins to neck at a true strain = 0.28 with a corresponding true stress =…

Q: Testing a round steel alloy bar with a diameter of 15 mm and a gauge length of 250 mm produced the…

A: Draw the cure with markings:

Q: Data taken from a stress-strain test for a brittle alloy are given in the table. The curve is linear…

A: , ksi, in/in0034.30.000843.50.001347.00.001749.00.002149.50.0023The rupture stress,

Q: A steel solid is subjected to following set of principal stresses: o1 = 300 MPa and o2 = 250 MPa.…

Q: 3. The distribution of stress in an aluminum machine component is given (in megapascals) by Ox = y +…

A: The stress tensor is:

Q: A steel bar is connected to an aluminum bar as shown below. At 70 F, the stresses in the steel and…

Q: Material Yield Tensile Strain at Fracture Elastic Strength StrengthFractureStrengthModulus (MPa)…

A: a) For material to experience the greatest percentage reduction in the area it should have a higher…

Q: The assembly shown consists of an aluminum shell (E, = 70 GPa, aą = 23.6 × 106PC) fully bonded to a…

A: We will use equillibrium and Axial deformation equation.

Concept explainers

Landfills

The landfill is a site used for the disposal of waste materials. The landfill is a solid waste facility that is often known as a dumping ground. The image below shows a landfill site in Hawaii. Landfilling is the most ancient and common method used for the disposal of waste. For the landfill, a deep trench is constructed in an isolated place away from the city. The trench for landfills is designed properly after analyzing the total population and the waste generation per capita. The waste is dumped into the trench and after every layer of waste, a layer of soil is spread on the top of it.

Question

Given your understanding of what initiates and controls failure in materials, which of the following will increase the failure strength or lifetime of a
test piece or component and why?
a. Decreasing the difference between the maximum and minimum stress values, as this effects the stress concentration factor
b. Decreasing the temperature below the brittle-ductile transition temperature, to make it harder
C. Polishing to reduce surface defects
Od. Increasing its volume, to give a larger cross sectional area
Oe. Increasing the grain size so there are less grain boundaries to initiate failure

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

A steel specimen is tested in tension. The specimen is 25 mm wide by 12.5 mm thick in the test region. By monitoring the load dial of the testing machine, it was found that the specimen yielded at a load of 160 kN and fractured at 214 kN. a. Determine the tensile stress at yield and at fracture. b. If the original gauge length was 100 mm, estimate the gauge length when the specimen is stressed to 1/2 the yield stress.
The following shaft is composed of two materials, both rigidly bonded. The data is provided in the table: Determine: The maximum torque that can be applied based on the maximum stresses of each material. The total deformation of the shaft with the torque from the previous section. The maximum torque that can be applied if the maximum deformation of the shaft is 2.50 rad.
Testing a round steel alloy bar with a diameter of 15 mm and a gauge length of 250 mm produced the stress-strain relationship shown in Figure P3.28. Determine a. the elastic modulus b. the proportional limit c. the yield strength at a strain offset of 0.002 d. the tensile strength e. the magnitude of the load required to produce an increase in length of 0.38 mm f. the final deformation, if the specimen is unloaded after being strained by the amount specified in (e) g. In designing a typical structure made of this material, would you expect the stress applied in (e) reasonable? Why? 750 500 250 0.01 0.02 0.03 0.04 Strain, m/m FIGURE P3.28 Stress, MPa
An extruded polymer beam is subjected to a bending moment M. The length of the beam is L = 740 mm. The cross-sectional dimensions of the beam are b1= 35 mm, d1= 101 mm, b2 = 21 mm, d2 21 mm, and a = 7 mm. For this material, the allowable tensile bending stress is 13 MPa, and the allowable compressive bending stress is 13 MPa. Determine the largest moment M that can be applied as shown to the beam. %3D b2 M. d2 di 14 L. b1 Answer: N-m M = %3D
Problem 1 An aluminum rod is rigidly attached between a steel rod and a bronze rod as shown. Axial loads are applied at the positions indicated. Aluminum Steel A=800mm2 A=1000mm2 Bronze A=700mm? 4P 2P 500mm 600mm 700mm 1. What is the maximum value of P that will not exceed the axial stress bronze of 105 MPa? 2. What is the maximum value of P that will not exceed the axial stress in aluminum of 90 MPa? 3. If P=10KN, what is the axial force to be carried by the aluminum in KN? 4. If P is 5KN, what is the axial stress of steel?
A cylindrical metal specimen 12.7 mm (0.5 in.) in diameter and 250 mm (10 in.) long is to be subjected to a tensile stress of 28 MPa (4000 psi); at this stress level, the resulting deformation will be totally elastic. (a) If the elongation must be less than 0.080 mm (3.2 x 10-3 in.), which of the metals in Table 6.1 are suitable candidates? O Steel O Nickel Brass O Magnesium O Aluminum O Copper O Titanium O Tungsten (b) If, in addition, the maximum permissible diameter decrease is 1.2 x 103 mm (4.7 × 105 in.) when the tensile stress of 28 MPa is applied, which of the metals that satisfy the criterion in part (a) are suitable candidates? O Aluminum O Magnesium O Steel O Tungsten O Copper O Brass O Titanium O Nickel
Q1/ Consider the brass alloy for which the stress-strain behavior is shown in the figure below. A cylindrical specimen of this material 10.0 mm in diameter and 101.6 mm long is pulled in tension with a force of 10,000 N. If it is known that this alloy has a value for Poisson's ratio of 0.35, compute (a) the specimen elongation, and (b) the reduction in specimen diameter. 500 70 Tensile strength 450 MPa (65,000 psi) 60 400 50 10 psi 300 MPa 40 40 30 200 Yield strength 30 200 250 MPa (36,000 psi) 20 100 20 10 100 10 0.005 0.10 0.20 0.30 0.40 Strain Stress (MPa) Stress (10 psi)