Given the three phase circuit illustrated below. Two balanced loads and the capacitors areconnceted to a 50 Hz balanced three phase line. The line to line voltage at the load is 500 Volts(rms). The line impedances are Zı=1.25+j1.25 2 per phase.V,500 VoltZ-1.25+jl.25 2200C=" (µF)LOAD 15 kWpf=1.0LOAD 215 kWpf=0.707 (lag)b) Calculate the line-to-line voltage Vs at the source.c) Calculate the power factor seen from the source.

In the power system Calculate line to line voltage Vs Find the power factor of the source

Given the three phase circuit illustrated below. Two balanced loads and the capacitors are connceted to a 50 Hz balanced three phase line. The line to line voltage at the load is 500 Volts (rms). The line impedances are Zı=1.25+jl.25 2 per phase. v, 500 Volt Z-1.25+jl.25 Q 200 C= LOAD 1 5 kW pf=1.0 LOAD 2 IS kW pf-0.707 (lag) b) Calculate the line-to-line voltage Vs at the source. c) Calculate the power factor seen from the source.

Given the three phase circuit illustrated below. Two balanced loads and the capacitors are connceted to a 50 Hz balanced three phase line. The line to line voltage at the load is 500 Volts (rms). The line impedances are Zı=1.25+jl.25 2 per phase. v, 500 Volt Z-1.25+jl.25 Q 200 C= LOAD 1 5 kW pf=1.0 LOAD 2 IS kW pf-0.707 (lag) b) Calculate the line-to-line voltage Vs at the source. c) Calculate the power factor seen from the source.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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