https://2u.pw/252Y5 Hello sir, I have an experiment topic, but I just want a graph that is required of me. I will send you a direct link so you can see my experience in pdf format for you to solve

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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https://2u.pw/252Y5 Hello sir, I have an experiment topic, but I just want a graph that is required of me. I will send you a direct link so you can see my experience in pdf format for you to solve
5. Graphs and Calculations:
1. From the data in Table (1), draw a graph of a diode current (vertical
axis) versus diode voltage.
دانود
2. Find the forward resistance (static & Dynamic) for each diode.
3. Find the reverse resistance (static & Dynamic) for, each diode.
دا بود
Supply
Voltage (Volts)
0
1
2
3
4
5
6
7
8
9
16
O
T
2
3
✓
5
6
4
9
9
10
469 mv
571 MV
624
Forword
VI(V)
660
686
ww
mr
725
741
454
mv
466 mV
MV
mv
0
519 mv
548 mv
561
MV
5% mv
577 mv
582
mv
587 Mv
540
MV
594 mr
597 Mv
Is (A)
0
2.3 MA
3.3
4.3
5.2
6.2
7,2
530 A
1.4 MA 1.4v
8,2
9.2
Reverse
V₁(V)
480 UA
1.45 MA
2.4 MA
3.4 MA
4.4 ша
5.4 MA
6.4 MA
0
7.4 MA
8.4 MA
9.4 MA
3=46
-994mv-5.1 UA
-3.9 UA
-2.7
MA 3.49 V
MA 4,4V
-5.955 UA
MA 5.93.156 UA
MA-611-5.959 UA
MA 9.1 - 5.958 UA
MA 5.9 -5.25404
-5.96 UA
MA-1.9V
0
- 119 MV
- 2 v
I. (A)
- 299V
3.99 V
4.89 V
- 4,1% V
4.95 V
0
-5.95 UA
-5.954 A
O
-2. NA
- 40 1.9 NA
-602 14
- 8.3.8 NA
- 105 UA
- 1.65 MA
- 2.04 MA.
3.03 MA
4.962 V
4.968V - 4.03 MA
4.44 V
- 5.02 MA
Transcribed Image Text:5. Graphs and Calculations: 1. From the data in Table (1), draw a graph of a diode current (vertical axis) versus diode voltage. دانود 2. Find the forward resistance (static & Dynamic) for each diode. 3. Find the reverse resistance (static & Dynamic) for, each diode. دا بود Supply Voltage (Volts) 0 1 2 3 4 5 6 7 8 9 16 O T 2 3 ✓ 5 6 4 9 9 10 469 mv 571 MV 624 Forword VI(V) 660 686 ww mr 725 741 454 mv 466 mV MV mv 0 519 mv 548 mv 561 MV 5% mv 577 mv 582 mv 587 Mv 540 MV 594 mr 597 Mv Is (A) 0 2.3 MA 3.3 4.3 5.2 6.2 7,2 530 A 1.4 MA 1.4v 8,2 9.2 Reverse V₁(V) 480 UA 1.45 MA 2.4 MA 3.4 MA 4.4 ша 5.4 MA 6.4 MA 0 7.4 MA 8.4 MA 9.4 MA 3=46 -994mv-5.1 UA -3.9 UA -2.7 MA 3.49 V MA 4,4V -5.955 UA MA 5.93.156 UA MA-611-5.959 UA MA 9.1 - 5.958 UA MA 5.9 -5.25404 -5.96 UA MA-1.9V 0 - 119 MV - 2 v I. (A) - 299V 3.99 V 4.89 V - 4,1% V 4.95 V 0 -5.95 UA -5.954 A O -2. NA - 40 1.9 NA -602 14 - 8.3.8 NA - 105 UA - 1.65 MA - 2.04 MA. 3.03 MA 4.962 V 4.968V - 4.03 MA 4.44 V - 5.02 MA
Expert Solution
Step 1

The given experimental data tables are shown below.

Electrical Engineering homework question answer, step 1, image 1

As it is asked only to draw the graph, so we are only providing the graphs of diode current (vertical axis) vs. diode voltage for both the diodes.

steps

Step by step

Solved in 3 steps with 5 images

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