Given the listed average bond energies (BE), calculate the enthalpy change for the production of one mole of methanol(CH3OH) by the following reaction. (There are two C=O double bonds in CO)CO2(g) + 3 H2(g) - CH;OH(g) + H2O(g)B.E.C-O = 300 kJ/molB.E.C=0 = 700 kJ/molB.E.H-H = 450 kJ/molB.E.H-O = 500 kJ/molB.E.H-C = 400 kJ/molSelect one:Oa.250 kJO b. -250 kJОс. 50 kJd.-950 kJActivate WindowsО е. 950 kJGo to Settings to activate Windows.

To solve this problem we will use the given bond energy

Given the listed average bond energies (BE), calculate the enthalpy change for the production of one mole of methanol (CH3OH) by the following reaction. (There are two C=O double bonds in CO2) CO-(g) + 3 H2(g) - CH;OH(g) + H2O(g) B.E.C-O = 300 kJ/mol B.E.C=o = 700 kJ/mol B.E.H-H = 450 kJ/mol B.E.H-O = 500 kJ/mol %3D B.E.H-C = 400 kJ/mol Select one: O a. 250 kJ O b. -250 kJ O c. 50 kJ O d. -950 kJ Activate Windows O e. 950 kJ Go to Settings to activate Windows.

Given the listed average bond energies (BE), calculate the enthalpy change for the production of one mole of methanol (CH3OH) by the following reaction. (There are two C=O double bonds in CO2) CO-(g) + 3 H2(g) - CH;OH(g) + H2O(g) B.E.C-O = 300 kJ/mol B.E.C=o = 700 kJ/mol B.E.H-H = 450 kJ/mol B.E.H-O = 500 kJ/mol %3D B.E.H-C = 400 kJ/mol Select one: O a. 250 kJ O b. -250 kJ O c. 50 kJ O d. -950 kJ Activate Windows O e. 950 kJ Go to Settings to activate Windows.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Given the listed average bond energies (BE), calculate the enthalpy change for the production of one mole of methanol (CH3OH) by the following reaction. (There are two C=O double bonds in CO2) CO2(g) + 3 H2(g) → CH3OH(g) + H2O(g) B.E.C–O = 300 kJ/mol B.E.C=O = 700 kJ/mol B.E.H–H = 450 kJ/mol B.E.H–O = 500 kJ/mol B.E.H–C = 400 kJ/mol Select one: a. 250 kJ b. 950 kJ c. -250 kJ d. 50 kJ e. -950 kJ
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