The combustion of 0.1566 g benzoic acid increases the temperature of a bomb calorimeter by 2.51°C. Calculate the heat capacity of this calorimeter. (The energy released by combustion of benzoic acid is 26.42 kJ/g.) Heat capacity = | |kJ/°C A 0.2195-g sample of vanillin (C¿Hg O3) is then burned in the same calorimeter, and the temperature increases by 3.21°C. What is the energy of combustion per gram of vanillin? Energy =| |kJ/g Per mole of vanillin? Energy = kJ/mol

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**Calorimetry Experiment: Determining Heat Capacity and Energy of Combustion**

In this experiment, the combustion of a sample is used to determine the heat capacity of a bomb calorimeter and the energy of combustion of another compound.

**Heat Capacity Calculation:**

The combustion of 0.1566 g of benzoic acid results in a temperature increase of 2.51°C in the bomb calorimeter. Given that the energy released by the combustion of benzoic acid is 26.42 kJ/g, calculate the heat capacity of the calorimeter.

- **Heat Capacity =** \_\_\_\_ kJ/°C

**Combustion of Vanillin:**

A 0.2195 g sample of vanillin (C₈H₈O₃) is burned in the same calorimeter, causing the temperature to increase by 3.21°C. Determine the energy of combustion per gram and per mole of vanillin.

- **Energy =** \_\_\_\_ kJ/g

- **Energy per mole of vanillin =** \_\_\_\_ kJ/mol

**Note:** Fill in the blanks with your calculated values.
Transcribed Image Text:**Calorimetry Experiment: Determining Heat Capacity and Energy of Combustion** In this experiment, the combustion of a sample is used to determine the heat capacity of a bomb calorimeter and the energy of combustion of another compound. **Heat Capacity Calculation:** The combustion of 0.1566 g of benzoic acid results in a temperature increase of 2.51°C in the bomb calorimeter. Given that the energy released by the combustion of benzoic acid is 26.42 kJ/g, calculate the heat capacity of the calorimeter. - **Heat Capacity =** \_\_\_\_ kJ/°C **Combustion of Vanillin:** A 0.2195 g sample of vanillin (C₈H₈O₃) is burned in the same calorimeter, causing the temperature to increase by 3.21°C. Determine the energy of combustion per gram and per mole of vanillin. - **Energy =** \_\_\_\_ kJ/g - **Energy per mole of vanillin =** \_\_\_\_ kJ/mol **Note:** Fill in the blanks with your calculated values.
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