Given the following function, what happens if a[] contains just one element that doesn't match val? int binarySearch(int a[], int first, int last, int val) { if (first > last) return -1; int middle = (first + last) / 2; if (a[middle] == val) return middle; if (a[middle] < val) return binarySearch(a, middle+1, last, val); else return binarySearch(a, first, middle-1, val); } Group of answer choices binarySearch never calls itself again and terminates (recursion never happens) binarySearch calls
Given the following function, what happens if a[] contains just one element that doesn't match val? int binarySearch(int a[], int first, int last, int val) { if (first > last) return -1; int middle = (first + last) / 2; if (a[middle] == val) return middle; if (a[middle] < val) return binarySearch(a, middle+1, last, val); else return binarySearch(a, first, middle-1, val); } Group of answer choices binarySearch never calls itself again and terminates (recursion never happens) binarySearch calls
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
Given the following function, what happens if a[] contains just one element that doesn't match val?
int binarySearch(int a[], int first, int last, int val)
{
if (first > last) return -1;
int middle = (first + last) / 2;
if (a[middle] == val) return middle;
if (a[middle] < val) return binarySearch(a, middle+1, last, val);
else return binarySearch(a, first, middle-1, val);
}
Group of answer choices
binarySearch never calls itself again and terminates (recursion never happens)
binarySearch calls itself once then terminates (recursion happens once)
binarySearch calls itself twice then terminates (recursion happens twice)
binarySearch calls itself 3 times then terminates (recursion happens 3 times)
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