def myfun ( x: Int, if x 0)': string) : String - { y + x, toString } else { myfun( x - 2 , "world" ) + myfun( x - 1, "hello") } ill in the missing part of the CPS transformation of the above function: def myfun_cps[T) x Int, y : String, k : ???1 => T) : T = { if (x = 0) ???2 } else { myfun_cps ( ??73, "world", (v1) => { myfun_cps( ??74, ???5, (v2) { ???6 } ) } ) 2??1 String 2??2 k(y + x.toString) 2??3 x-2 2??4 [ Choose) 2??5 V ( Choose ) "world" k(y + x.toString) y + x.toString ???6 "hello" x-2 String Int k(v1+v2) Question 2 x-1 k(v1 - v2) > > >

Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Related questions
Question
def myfun ( x: Int, y: String) : String = {
if (x <= 0) {
y + x. toString
} else {
myfun( x - 2 , "world" ) + myfun( x
1, "hello")
}
Fill in the missing part of the CPS transformation of the above function:
def myfun_cps[T)( x : Int, y : String, k : ???1 => T) : T = {
if (x 0) {
???2
} else {
myfun_cps ( ???3 , "world",
(v1) => { myfun_cps( ???4, ???5,
(v2) =>( ???6 } )
} )
???1
String
???2
k(y + x.toString)
???3
х-2
???4
Choose]
V [ Choose ]
???5
"world"
k(y + x.toString)
y + x.toString
???6
"hello"
х-2
String
Int
k(v1+v2)
Question 2
x-1
k(v1 - v2)
v1 + v2
v1 - v2
Transcribed Image Text:def myfun ( x: Int, y: String) : String = { if (x <= 0) { y + x. toString } else { myfun( x - 2 , "world" ) + myfun( x 1, "hello") } Fill in the missing part of the CPS transformation of the above function: def myfun_cps[T)( x : Int, y : String, k : ???1 => T) : T = { if (x 0) { ???2 } else { myfun_cps ( ???3 , "world", (v1) => { myfun_cps( ???4, ???5, (v2) =>( ???6 } ) } ) ???1 String ???2 k(y + x.toString) ???3 х-2 ???4 Choose] V [ Choose ] ???5 "world" k(y + x.toString) y + x.toString ???6 "hello" х-2 String Int k(v1+v2) Question 2 x-1 k(v1 - v2) v1 + v2 v1 - v2
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