Problem: Substring Pattern Matching Input: A text string t and a pattern string p Output: Does t contain the pattern p as a substring, and if so, where? For example: with t = abaababbaba, p = abba, your function should return 5. int findmatch(char *p, char *t) { int plen = strlen(p); // len of string p int tlen = strlen(t); // len of string t // TODO: your code Analyze your algorithm: what is the big O?

Problem: Substring Pattern Matching Input: A text string t and a pattern string p Output: Does t contain the pattern p as a substring, and if so, where? For example: with t = abaababbaba, p = abba, your function should return 5. int findmatch(char p, char t) { int plen = strlen(p); // len of string p int tlen = strlen(t); // len of string t // TODO: your code Analyze your algorithm: what is the big O?

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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C+++ CODE QUESTION PLEASE SEE ATTACHED IMAGE ALSO Print the two strings, firstString and secondString, in alphabetical order. Assume the strings are lowercase. End with newline. Sample output: capes rabbits #include <iostream> #include <string> using namespace std; int main() { string firstString; string secondString; cin >> firstString; cin >> secondString; return 0; }
Match the std::string constructor on right to its function on left. Source: https://cplusplus.com/reference/string/string/string/ E string() string (const string& str) string (const char* s) string (size_t n, char c) [Choose] [Choose ] constructs a copy of str. constructs an empty string, with a length of zero characters. copies the null-terminated character sequence (C-string) pointed by s. fills the string with n consecutive copies of character c. [Choose ]
Python question Analysis: Invariants (Q16-17) For each of the following functions, identify the loop invariant, exit condition and post condition. Question 16 (Invariant 1) This function returns the list of integers that are multiples of both 3 and 7 that occurs within a given list. Identify the loop exit condition, the loop post-condition, and the loop invariant at the end of the loop, which shows the algorithm’s correctness. def multiples_count(lst): """ Input: a list of integers, lst Output: the list of integers in lst that are multiples of both 3 and 7 """ res = [] for i in range(len(lst)): if lst[i]%3 == 0 and lst[i]%7 == 0: res.append(lst[i]) # Identify the loop invariant here return res Question 17 (Invariant 2) This function checks if a given list (of comparable elements) is sorted in ascending order. Identify the loop exit condition, the loop post-condition, and the loop invariant at the end of each iteration of the loop, which…
String orig_string is read from input. Assign variable sliced_string with the orig_string slice that excludes the characters at indices 10 and 11.
What input or parameter value impacts the number of times the recursive function will be called. • Give three specific examples of input/parameter values and, for each, state the number of times the recursive function will be called. • Devise a formula with respect to n that describes the number of times the recursive function will be called, where n is either the value passed or some property of the value passed (e.g. n might be the length of a string of the size of an array).
The mapped list pattern Our second pattern is the mapped list pattern, described in video 4 3 mapped list pattern. Often we need to write a function that takes a list as a parameter and returns a new list in which each item in the original list is "mapped" to a new item in the result list. For example, the following function takes a list of numbers as a parameter and returns a list of all the numbers squared, e.g. squares ( [1, 3, 7]) returns [1, 9, 49]. def squares (nums): "Returns the squares of the given numbers""" result = [] for num in nums: result.append (num * num) return result Although this is just a special case of the accumulator pattern, it is so common that we give it its own name: the mapped list pattern. Consider the following function: def squares(nums): ""Returns the squares of the given numbers""" result = [] for num in nums: result.append (num * num) return result If the main program calls print(squares ( [5, -3, 2, 7]) what is the state table for the function…
Write the countVowels function which counts the number of vowels using the string class as follows: int countVowels(const string& s) Write a test program that prompts the user to enter a string, invokes the countVowels function and displays the total number of vowels in the string.
5. use c code to Write a stringSearch function that gets two strings one called needle and the other called haystack. It then searches in the Haystack for the needle. If it finds it, it returns the index of where the needle starts in the haystack. If the needle cannot be found, it should return -1 Prototype: int stringSearch(char needle[], char haystack) Example1: Haystack: “This is just an example” Needle: “just” Result: 8 Example2: Haystack: “This is just an example” Needle: “This” Result: 0 Example3: Haystack: “This is just an example” Needle: “this” Result: -1 Hint: all the answer need to include an output and use c code to answer
1c) Average sentence length We will create a function (avg_sentence_len) to calculate the average sentence length across a piece of text. This function should take text as an input parameter. Within this function: sentences: Use the split() string method to split the input text at every '.'. This will split the text into a list of sentences. Store this in the variable sentences. To keep things simple, we will consider every "." as a sentence separator. (This decision could lead to misleading answers. For example, "Hello Dr. Jacob." is actually a single sentence, but our function will consider this 2 separate sentences). words: Use the split() method to split the input text into a list of separate words, storing this in words. Again, to limit complexity, we will assume that all words are separated by a single space (" "). (So, while "I am going.to see you later" actually has 7 words, since there is no space after the ".", so we will assume the this to contain 6 separate words in our…